Measures of Dispersion
Range, quartile deviation and mean deviation
The range is the largest value minus the smallest. It is quick and easily distorted by one extreme value. The quartile deviation (semi-interquartile range) uses only the middle half: Q.D. = (Q₃ − Q₁)/2, so it ignores the extreme quarters and suits open-end distributions. The mean deviation averages the absolute distances from a centre: M.D. = Σ|x − A|/n, and it is smallest when A is the median.
Worked: for 4, 8, 6, 10, 12 the mean is 8; the absolute deviations are 4, 0, 2, 2, 4, so M.D. about the mean = 12/5 = 2.4; the range is 12 − 4 = 8 and its coefficient is 8/16 = 0.5.
Standard deviation and variance
The standard deviation squares the deviations instead of dropping their signs, averages them and takes the square root: σ = √(Σ(x − x̄)²/n). Its square σ² is the variance. A convenient form is σ² = Σx²/n − x̄² ('mean of squares minus square of mean'), and for grouped data σ² = Σfx²/N − x̄², or with step deviations σ = h√(Σfu²/N − (Σfu/N)²).
| x | x − x̄ | (x − x̄)² |
|---|---|---|
| 4 | -4 | 16 |
| 8 | 0 | 0 |
| 6 | -2 | 4 |
| 10 | 2 | 4 |
| 12 | 4 | 16 |
| Total | 0 | 40 |
σ² = 40/5 = 8 and σ = √8 ≈ 2.83. Check with the short form: Σx² = 360, 360/5 − 8² = 72 − 64 = 8.
Change of origin and scale. If y = a + bx, then σᵧ = |b|·σₓ and Var(y) = b²·Var(x). Adding a constant moves the data without spreading it, so the SD is unchanged; multiplying by b stretches it by |b|. Two standard results: the SD of the first n natural numbers is √((n² − 1)/12), and for two values a and b the SD is |a − b|/2.
Coefficient of variation and combined SD
The coefficient of variation C.V. = (σ ÷ x̄) × 100 expresses the SD as a percentage of the mean. The series with the smaller C.V. is more consistent (more stable, more homogeneous). For 4, 8, 6, 10, 12, C.V. = 2.83/8 × 100 ≈ 35.4%.
For two groups of sizes n₁, n₂ with means x̄₁, x̄₂ and SDs σ₁, σ₂, the combined variance is σ² = [n₁(σ₁² + d₁²) + n₂(σ₂² + d₂²)] ÷ (n₁ + n₂), where d₁ = x̄₁ − x̄ and d₂ = x̄₂ − x̄ measure how far each group's mean sits from the combined mean. Forgetting the d² terms understates the spread whenever the group means differ.
Exam traps and a quick revision
- Range and Q.D. use two values each; M.D. and S.D. use every value.
- S.D. is unchanged by a change of origin and changes by |b| with a change of scale.
- Smaller C.V. = more consistent, whatever the raw SDs say.
- SD of 1, 2, …, n is √((n² − 1)/12); SD of two numbers is half their difference.
- Variance can never be negative; it is zero only when all values are equal.
Key takeaways
- Absolute measures carry the data's units; coefficients are pure numbers that compare series.
- Q.D. = (Q₃ − Q₁)/2; M.D. is least about the median; σ² = Σx²/n − x̄².
- For y = a + bx: σᵧ = |b|σₓ and Var(y) = b²Var(x).
- C.V. = σ/x̄ × 100; the lower C.V. marks the more consistent series.
- Combined variance adds each group's d² = (x̄ᵢ − x̄)² to its own variance before weighting.
Practice questions (10)
Attempt each one before opening the answer. Every explanation names the tempting wrong option as well as the right one, because that is where marks are lost.
Which measure of dispersion is based only on the middle 50% of the observations?
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Answer: B — quartile deviation
Q.D. = (Q₃ − Q₁)/2 uses only the stretch between the first and third quartiles, which holds the middle half of the data. The range uses only the two extremes.If 10 is added to every observation, the standard deviation:
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Answer: A — remains unchanged
Adding a constant shifts every value and the mean by the same amount, so every deviation x − x̄ is unchanged and so is σ.The variance of a variable X is 9. The variance of Y = 5 − 2X is:
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Answer: D — 36
Var(a + bX) = b²·Var(X) = (−2)² × 9 = 36. The constant 5 has no effect, and the negative sign disappears on squaring.The standard deviation of the observations 4, 8, 6, 10, 12 is:
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Answer: A — 2√2
Mean = 8; squared deviations 16, 0, 4, 4, 16 sum to 40; variance = 40/5 = 8 and σ = √8 = 2√2 ≈ 2.83. 8 is the variance and 2.4 the mean deviation.Batsman A averages 50 runs with SD 10; batsman B averages 40 runs with SD 9. Which is more consistent, and why?
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Answer: D — A, because his C.V. is lower
Consistency is judged by the coefficient of variation: A = 10/50 × 100 = 20%, B = 9/40 × 100 = 22.5%. A's lower C.V. makes him more consistent even though his SD is larger.For a distribution Q₁ = 30 and Q₃ = 50. The coefficient of quartile deviation is:
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Answer: A — 0.25
Coefficient of Q.D. = (Q₃ − Q₁)/(Q₃ + Q₁) = 20/80 = 0.25. The quartile deviation itself is 20/2 = 10.The standard deviation of the first 9 natural numbers 1, 2, …, 9 is:
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Answer: A — √(20/3)
SD of 1 to n = √((n² − 1)/12) = √(80/12) = √(20/3) ≈ 2.58. 20/3 is the variance.The coefficient of variation is defined as:
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Answer: B — (standard deviation ÷ mean) × 100
C.V. = σ/x̄ × 100, the SD as a percentage of the mean. It is a pure number, which is what lets it compare series in different units.Group A has 10 items with mean 20 and variance 4; group B has 10 items with mean 30 and variance 4. The variance of all 20 items together is:
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Answer: C — 29
Combined mean = 25, so d₁ = −5 and d₂ = 5. σ² = [10(4 + 25) + 10(4 + 25)]/20 = 29. Averaging only the two variances gives 4 and ignores the gap between the group means.For a normal distribution with standard deviation 15, the quartile deviation is approximately:
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Answer: D — 10
For a normal distribution Q.D. ≈ (2/3)σ = 10 and M.D. ≈ (4/5)σ = 12. The ratio Q.D. : M.D. : S.D. ≈ 10 : 12 : 15 is exactly this case.