Evolution: Origin and History of Life, Theories, Natural Selection, Adaptation and Speciation
2. History of life: the geological record
Ages come from radiometric dating: a parent isotope decays with a fixed half-life, so the fraction left after n half-lives is (1/2)ⁿ. Carbon-14 (half-life about 5,730 years) dates material up to roughly 50,000 years old; uranium–lead and potassium–argon date rocks billions of years old.
| About how long ago | Event |
|---|---|
| 4.5 billion years | Earth forms |
| 3.5 billion years | Oldest widely accepted fossils: stromatolites and prokaryotic microfossils |
| 2.4 billion years | Great Oxidation Event: oxygen from cyanobacterial photosynthesis accumulates in the atmosphere |
| 1.8 billion years | Oldest widely accepted eukaryotic fossils |
| 570 million years | Ediacaran biota: large soft-bodied multicellular organisms |
| 540 million years | Cambrian explosion: most animal phyla with hard parts appear in a geologically short time |
| 375 million years | Devonian lobe-finned fishes give rise to tetrapods (Tiktaalik) |
| 252 million years | End-Permian extinction, the largest; ends the Palaeozoic |
| 230 to 200 million years | Triassic: first dinosaurs and, late in the period, first mammals |
| 150 million years | Jurassic Archaeopteryx, a feathered dinosaur with bird features |
| 66 million years | End-Cretaceous extinction after an asteroid impact removes non-avian dinosaurs; mammals radiate |
| 300,000 years | Homo sapiens in Africa |
The Phanerozoic has three eras. The Palaeozoic (Cambrian, Ordovician, Silurian, Devonian, Carboniferous, Permian) saw the rise of animal phyla, fishes (the Devonian is the “Age of Fishes”), land plants, amphibians and the first amniotes. The Mesozoic (Triassic, Jurassic, Cretaceous) was the age of reptiles, with the first mammals, birds and flowering plants. The Cenozoic (Paleogene, Neogene, Quaternary) is the age of mammals. Five mass extinctions stand out: end-Ordovician, Late Devonian, end-Permian, end-Triassic and end-Cretaceous. Each emptied niches that survivors filled by adaptive radiation.
3. Theories of evolution and the molecular clock
| Theory | Core claim | Verdict |
|---|---|---|
| Lamarckism (Lamarck, 1809) | Organs grow with use and shrink with disuse, and such acquired characters are inherited | Rejected: Weismann's germ-plasm theory separates soma from germ line; mice whose tails were cut for several generations still bore tailed young |
| Darwinism (Darwin and Wallace, 1858; On the Origin of Species, 1859) | Overproduction, heritable variation and the struggle for existence let the better-suited leave more offspring; all life shares common descent | Core accepted; Darwin lacked a correct theory of heredity |
| Mutation theory (de Vries, early 1900s) | New species arise in one step by large mutations (Oenothera lamarckiana) | His “mutations” were mostly chromosomal changes; speciation is rarely a single jump |
| Modern synthesis (1930s–1940s: Fisher, Haldane, Wright, Dobzhansky, Mayr, Simpson) | Evolution is change in allele frequencies by mutation, selection, drift and gene flow; Mendelian genetics supplies the variation | The framework of present-day evolutionary biology |
| Neutral theory (Kimura, 1968) | Most molecular differences are selectively neutral and fixed by drift; neutral substitution rate = neutral mutation rate | Explains the molecular clock; selection still shapes adaptive traits |
| Punctuated equilibrium (Eldredge and Gould, 1972) | Long stasis broken by rapid change concentrated at speciation | Contrasted with phyletic gradualism; both patterns occur |
The evidence for descent with modification is concordant: transitional fossils (Tiktaalik, Archaeopteryx); homologous and vestigial structures (the pentadactyl limb; the human coccyx); pharyngeal arches in all vertebrate embryos; island species resembling those of the nearest mainland; and molecular homology, from the near-universal genetic code to sequence differences (as in cytochrome c) that match the tree built from anatomy.
Molecular clock. If substitutions accumulate at a steady rate r per site per year in each lineage, the distance between two species that split T years ago is K = 2rT, because both lineages change after the split; hence T = K/(2r). Worked example: K = 0.1 substitutions per site and r = 1 × 10⁻⁹ per site per year give T = 0.1/(2 × 10⁻⁹) = 50 million years. Rates differ between genes and lineages (faster in species with short generations), so a clock is calibrated with dated fossils and tested, for example by a relative-rate test against an outgroup.
4. Natural selection: fitness and allele-frequency change
Natural selection needs variation, heritability and differential reproductive success. It acts on phenotypes but changes genotype and allele frequencies. Absolute fitness W of a genotype is its mean number of offspring that survive to breed, the product of survival and fecundity. Relative fitness w = W/W_max sets the best genotype to 1, and the selection coefficient s = 1 − w measures its disadvantage. Example: if AA, Aa and aa survive to adulthood with probabilities 0.8, 0.8 and 0.5 and lay 50, 50 and 40 eggs, then W = 40, 40 and 20, w = 1, 1 and 0.5, and s = 0.5 against aa.
Allele-frequency change. Multiply each Hardy–Weinberg genotype frequency by its fitness and divide by the mean fitness w̄ = p²w_AA + 2pq·w_Aa + q²w_aa. For selection against a recessive (fitnesses 1, 1, 1 − s), w̄ = 1 − sq² and q′ = (pq + q²(1 − s))/w̄, so Δq = −sq²(1 − q)/(1 − sq²). Worked example: q = 0.4 and s = 0.5. Genotype frequencies are 0.36, 0.48 and 0.16; w̄ = 1 − 0.5 × 0.16 = 0.92; q′ = (0.24 + 0.08)/0.92 = 0.348, so Δq = −0.052 in one generation. As q falls, most copies of a hide in heterozygotes where selection cannot see them, and the decline slows. For a recessive lethal (s = 1), q_t = q₀/(1 + tq₀), so the generations needed are 1/q_t − 1/q₀: halving q from 0.02 to 0.01 takes 50 generations.
| Mode | What is favoured | Example |
|---|---|---|
| Directional | One extreme; the mean shifts | Industrial melanism; insecticide resistance |
| Stabilising | The intermediate; variance falls | Human birth weight, with infant survival highest at intermediate weights |
| Disruptive | Both extremes over intermediates; can split a population | Black-bellied seedcracker finches, whose large- and small-billed birds each crack a different seed type |
| Balancing | Keeps two or more alleles | Heterozygote advantage; negative frequency-dependent selection |
| Sexual | Traits that raise mating success | Male combat with antlers (intrasexual); female choice of the peacock's train (intersexual) |
Heterozygote advantage gives a stable polymorphism. With fitnesses 1 − s (AA), 1 (Aa) and 1 − t (aa), the equilibrium frequency of a is q̂ = s/(s + t), whatever the starting frequency. In malarial regions HbA/HbS heterozygotes resist severe Plasmodium falciparum malaria, HbA/HbA people suffer more malaria and HbS/HbS people have sickle-cell anaemia, so HbS persists at high frequency. For quantitative traits the response to selection is R = h²S, where S is the selection differential and h² the narrow-sense heritability.
5. Adaptation
An adaptation is a heritable trait that raises fitness in a given environment and was shaped by natural selection for its present role. Studied cases: industrial melanism in the peppered moth Biston betularia, whose dark (carbonaria) form rose to high frequency in soot-darkened woods of industrial Britain because birds took more of the conspicuous pale moths, and declined again after clean-air laws; bill depth in Darwin's ground finches, which rose after a drought on the Galápagos left mainly large, hard seeds; and DDT resistance in mosquitoes. In each case selection acts on variants already present; the agent does not induce the needed mutation.
Protective adaptations. Crypsis hides an animal against its background; aposematism advertises unpalatability with conspicuous warning colours. In Batesian mimicry a palatable species (hoverflies) copies a defended model (wasps); the benefit depends on predators meeting the model more often, so it falls as the mimic becomes common, a case of negative frequency dependence. In Müllerian mimicry two or more defended species (several Heliconius butterflies) share one warning pattern and so share the cost of educating predators.
Not every trait is an adaptation. A trait may be a by-product of another feature, may have been fixed by drift, or may reflect historical constraint: the vertebrate retina is wired with its nerve fibres in front of the photoreceptors, leaving a blind spot. An exaptation evolved for one role and was later co-opted for another; feathers, which arose before flight for insulation or display, are the standard case. Convergent evolution of one solution in unrelated lineages (the streamlined shape of sharks, ichthyosaurs and dolphins) is strong evidence that a trait is adaptive. Adaptive radiation is the rapid diversification of one lineage into many niches: Darwin's finches, Hawaiian honeycreepers and the cichlid fishes of the African Great Lakes.
6. Speciation
Under the biological species concept a species is a group of interbreeding natural populations reproductively isolated from other such groups, so speciation is the evolution of reproductive isolation. Barriers act before or after a zygote forms.
| Barrier | Stage | Example |
|---|---|---|
| Habitat | Prezygotic | Populations in one area use different habitats and rarely meet |
| Temporal | Prezygotic | Related species breed in different seasons or at different times of day |
| Behavioural | Prezygotic | Species-specific courtship songs, displays or firefly flash patterns |
| Mechanical | Prezygotic | Incompatible genitalia in many insects |
| Gametic | Prezygotic | Sea-urchin sperm bindin binds only eggs of its own species |
| Hybrid inviability | Postzygotic | Hybrid embryos die during development |
| Hybrid sterility | Postzygotic | The mule (horse 2n = 64, donkey 2n = 62, mule 2n = 63) cannot complete normal meiosis |
| Hybrid breakdown | Postzygotic | F1 hybrids are fertile but F2 or backcross progeny are weak or sterile |
Allopatric speciation starts with a geographic barrier. In vicariance the barrier divides a widespread population, as when the Isthmus of Panama, which closed about 3 million years ago, split marine animals into Pacific and Caribbean sister species. In peripatric speciation a small founder population at the edge of the range diverges fast through drift and new selection, as on islands. In parapatric speciation adjacent populations along an environmental gradient diverge despite some gene flow across a hybrid zone. Sympatric speciation needs no geographic separation: by polyploidy (common in plants, rare in animals), by a shift to a new host, as in the apple and hawthorn races of the fly Rhagoletis pomonella, which mate on their own host fruit, or by mate choice, as among cichlids. Where incompletely isolated populations meet and hybrids are unfit, selection strengthens prezygotic isolation: reinforcement.
Key takeaways
- Life arose by chemical evolution at least about 3.5 billion years ago; Miller–Urey made amino acids under reducing conditions, and ribozymes and rRNA catalysis of the peptide bond support an RNA world.
- Approximate ages: Earth 4.5 billion years, first fossils 3.5 billion, Great Oxidation 2.4 billion, eukaryotes 1.8 billion, Cambrian explosion 540 million, end-Permian 252 million and end-Cretaceous 66 million years ago.
- Inheritance of acquired characters failed; natural selection, joined to Mendelian genetics in the modern synthesis, stands. Neutral theory makes the substitution rate equal the neutral mutation rate, the basis of the molecular clock T = K/(2r).
- w = W/W_max and s = 1 − w; after selection q′ is the fitness-weighted share of a divided by w̄. Selection against a rare recessive is slow, and heterozygote advantage holds q̂ = s/(s + t).
- Adaptations are selected heritable traits, not responses to need; distinguish exaptations, by-products and constraints. Batesian mimicry is frequency-dependent; Müllerian mimicry shares the cost among defended species.
- Speciation is the evolution of reproductive isolation through prezygotic and postzygotic barriers, in allopatric, peripatric, parapatric or sympatric settings; reinforcement and Haldane's rule are the classic exam points.
Practice questions (18)
Attempt each one before opening the answer. Every explanation names the tempting wrong option as well as the right one, because that is where marks are lost.
In the 1953 experiment of Miller and Urey, electric sparks were passed through a mixture of CH₄, NH₃, H₂ and water vapour. What did the experiment produce?
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Answer: A — Amino acids such as glycine and alanine, formed from simple gases in a closed apparatus
The spark-discharge apparatus yielded simple organic monomers, notably amino acids such as glycine and alanine, showing that such molecules form abiotically under reducing conditions. It did not produce self-replicating RNA, protocells or long polypeptides; polymerisation and compartments are later steps studied in other experiments such as those on coacervates and proteinoid microspheres.Which observation gives the strongest support to the hypothesis that RNA preceded both DNA and proteins in early life?
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Answer: B — The peptidyl transferase activity of the ribosome resides in its rRNA
The RNA world needs a molecule that both carries information and catalyses; the fact that the ribosome's peptide-bond-forming centre is RNA is a molecular fossil of that stage. DNA's greater stability explains why DNA later took over storage, which is the tempting answer, but it says nothing about RNA coming first. Spark-discharge synthesis concerns monomers, and mitochondrial DNA is evidence for endosymbiosis.Which of the following observations support the endosymbiotic origin of mitochondria?
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Answer: A — Mitochondria carry their own circular DNA molecule; B — Mitochondrial ribosomes resemble bacterial ribosomes and are inhibited by chloramphenicol; C — Mitochondrial rRNA sequences are most similar to those of α-proteobacteria
Circular genomes, bacteria-like ribosomes sensitive to chloramphenicol and an rRNA affinity with α-proteobacteria all point to a bacterial ancestor. The claim that the organelle encodes all its own proteins is false: most mitochondrial proteins are encoded in the nucleus and imported, because most genes of the endosymbiont moved to the nuclear genome.Which sequence lists these events from the oldest to the most recent?
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Answer: C — Great Oxidation Event → oldest eukaryotic fossils → Cambrian explosion → end-Permian extinction
The Great Oxidation Event was about 2.4 billion years ago, the oldest widely accepted eukaryotic fossils are about 1.8 billion years old, the Cambrian explosion was about 540 million years ago and the end-Permian extinction about 252 million years ago. Placing eukaryotes before the oxygenation of the atmosphere is the commonest slip.Which mass extinction marks the boundary between the Palaeozoic and Mesozoic eras?
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Answer: B — The end-Permian extinction
The end-Permian extinction, about 252 million years ago and the largest of the five, closes the Palaeozoic and opens the Mesozoic. The end-Cretaceous extinction, about 66 million years ago, is the tempting answer but marks the Mesozoic–Cenozoic boundary. The end-Ordovician and Late Devonian events fall inside the Palaeozoic.Cave-dwelling populations of a fish species have reduced, non-functional eyes. Which explanation is Lamarckian rather than Darwinian or neutral?
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Answer: D — Eyes shrank in each generation through disuse in the dark, and the reduced eyes were inherited
Inheritance of a change acquired through disuse during life is Lamarck's mechanism. The energy-saving explanation is Darwinian selection on heritable variation, the drift explanation is neutral evolution under relaxed selection, and the linkage explanation is indirect selection by hitchhiking; all three involve changes in allele frequencies, not inheritance of acquired characters.In a diploid population of constant size N, neutral mutations arise at a rate μ per gene copy per generation. According to the neutral theory, the rate at which neutral substitutions become fixed in the population, per generation, is —
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Answer: A — μ, independent of population size
Each generation 2Nμ new neutral mutations arise among the 2N gene copies, and each has a probability 1/(2N) of drifting to fixation, so the substitution rate is 2Nμ × 1/(2N) = μ. Population size cancels, which is why neutral molecular change can tick like a clock. 2Nμ is tempting because it is the number of new mutations per generation, not the number fixed; 4Nμ is the parameter θ that governs neutral heterozygosity.Which of the following observations are consistent with the neutral theory of molecular evolution?
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Answer: A — Synonymous sites in protein-coding genes accumulate substitutions faster than non-synonymous sites; B — Pseudogenes, which no longer encode functional products, evolve at some of the highest rates in the genome; C — Histone H4, whose function tolerates almost no change, evolves very slowly
Neutral theory predicts that the less constrained a site, the larger the share of its mutations that are neutral and the faster it evolves: hence fast synonymous sites and pseudogenes and a slow, highly constrained histone H4. The neutral substitution rate equals the neutral mutation rate and does not depend on population size, so faster neutral substitution in larger populations contradicts the theory.In a randomly mating population at Hardy–Weinberg proportions, the frequency of a recessive allele a is 0.3. The relative fitnesses of AA, Aa and aa are 1, 1 and 0.6. After one generation of selection, the frequency of a is ____ (to three decimal places).
Numerical answer — type the value.
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Answer: 0.274
p = 0.7 and q = 0.3, so the genotype frequencies are AA 0.49, Aa 0.42 and aa 0.09. Mean fitness w̄ = 0.49 + 0.42 + 0.09 × 0.6 = 0.964. After selection q′ = (½ × 0.42 + 0.09 × 0.6)/0.964 = (0.21 + 0.054)/0.964 = 0.264/0.964 = 0.274. Forgetting to divide by w̄ gives 0.264.In an insect population, genotypes AA, Aa and aa survive to adulthood with probabilities 0.9, 0.9 and 0.6, and surviving females lay on average 40, 40 and 35 eggs respectively. Taking absolute fitness as survival × fecundity, the selection coefficient against aa is ____ (to two decimal places).
Numerical answer — type the value.
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Answer: 0.42
Absolute fitness: AA = 0.9 × 40 = 36, Aa = 36, aa = 0.6 × 35 = 21. Relative fitness of aa = 21/36 = 0.583, so s = 1 − 0.583 = 0.417, or 0.42 to two decimal places. Using survival alone gives s = 1 − 0.6/0.9 = 0.33, which ignores the fecundity component of fitness.At a locus showing heterozygote advantage, the relative fitnesses of AA, Aa and aa are 0.8, 1.0 and 0.5. The equilibrium frequency of allele a maintained by selection is ____ (to two decimal places).
Numerical answer — type the value.
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Answer: 0.29
With fitnesses 1 − s (AA), 1 (Aa) and 1 − t (aa), the stable equilibrium is q̂ = s/(s + t), where q is the frequency of a. Here s = 0.2 and t = 0.5, so q̂ = 0.2/0.7 = 0.286, or 0.29. Writing t/(s + t) = 0.71 gives the frequency of A instead, the usual mix-up: the allele whose homozygote is less fit ends up rarer.A gene differs between two mammal species by K = 0.08 substitutions per site. Assume a constant rate of r = 2 × 10⁻⁹ substitutions per site per year in each lineage, so that the divergence time is T = K/(2r). The two species diverged ____ million years ago.
Numerical answer — type the value.
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Answer: 20
Both lineages accumulate substitutions after the split, so K = 2rT and T = K/(2r) = 0.08/(2 × 2 × 10⁻⁹) = 0.08/(4 × 10⁻⁹) = 2 × 10⁷ years = 20 million years. Dividing by r alone, as if only one lineage had changed, gives 40 million years.In a population of seed-eating birds, the available seeds are either very small or very large and hard, and birds with intermediate bills feed poorly on both. Over several generations bill size becomes bimodal. Which mode of selection is acting?
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Answer: C — Disruptive selection, which favours both extremes over intermediates
When both extremes have higher fitness than intermediates, selection is disruptive and the distribution becomes bimodal. Stabilising selection is the tempting opposite: it acts against extremes. Directional selection would shift the whole distribution one way, and nothing in the scenario concerns mate choice.A harmless, palatable hoverfly carries yellow-and-black bands like those of a stinging wasp. Field studies show that the hoverfly gains less protection from birds where it is much more common than the wasp. Which phenomenon does this illustrate?
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Answer: D — Batesian mimicry, whose benefit falls as the mimic becomes common relative to its model
A palatable mimic of a defended model is a Batesian mimic. Predators learn to avoid the pattern from unpleasant encounters with the model; where mimics are common, birds meet them more often and learn less avoidance, so protection falls (negative frequency dependence). Müllerian mimicry is the tempting alternative, but it needs both species to be defended. The hoverfly is harmless, so its colours are not honest warning, and bands that attract attention are not crypsis.Which of the following statements about adaptation are correct?
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Answer: A — Feathers, which arose before flight and were later used for it, are an example of exaptation; B — The dark form of the peppered moth increased in soot-darkened woods and declined after air pollution fell
Feathers are the classic exaptation, and the rise and fall of melanic Biston betularia tracked pollution through bird predation. A common trait may be a by-product, a result of drift or a historical constraint, so commonness alone does not prove adaptation. Resistance alleles are present before exposure; the insecticide selects them but does not create them.In crosses between two closely related bird species, the F1 hybrids of one sex are sterile while those of the other sex are fertile. According to Haldane's rule, which sex is expected to be sterile?
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Answer: A — Females, because in birds the female is the heterogametic sex (ZW)
Haldane's rule names the heterogametic sex, which in birds is the ZW female, as the one absent, rare or sterile in hybrids. “Hybrid males are sterile” is the tempting overgeneralisation from mammals and Drosophila, where males are XY. Male birds are ZZ (homogametic), and birds do have sex chromosomes.Two populations of a fruit fly live in the same orchards. One lays eggs on apples and the other on hawthorn fruits; flies mate on the kind of fruit on which they developed, and apples ripen several weeks earlier than hawthorn fruits. Hybrids are viable and fertile in the laboratory. Which interpretation fits best?
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Answer: B — Sympatric divergence driven by a host shift, with habitat and temporal isolation acting before mating
The populations share one geographic area, and divergence follows a shift to a new host. Mating on the natal host (habitat isolation) and the earlier ripening of apples (temporal isolation) are prezygotic barriers, so this is sympatric divergence in progress. Fertile laboratory hybrids rule out postzygotic isolation as the barrier; trees in one orchard are not geographic barriers, and there is no spatial gradient of the kind parapatry requires.Which of the following are prezygotic isolating barriers?
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Answer: A — Two frog species breed in the same pond but in different months of the year; B — Sperm of one sea-urchin species cannot bind to the egg coat of a related species
Temporal isolation and gametic incompatibility (species-specific sperm–egg recognition through bindin) act before a zygote forms, so they are prezygotic. Mule sterility is hybrid sterility, and weak or sterile offspring of fertile F1 hybrids are hybrid breakdown; both are postzygotic.