Materials Science and Non-Metallic Materials: Bonding, Crystal Structure, Polymers, Ceramics, Composites, and Electronic and Magnetic Properties

Section 8 of the GATE Metallurgical Engineering (MT) paper, and its last, in one chapter that follows its six headings. The first is general: the classification of engineering materials; ionic, covalent, metallic and secondary bonding; and the structures of metals and alloys, of ionic and covalent solids, and of polymers — which is where the crystallography this paper computes with (lattices, packing factors, densities from lattice parameters, Miller indices and interplanar spacings) is set out. Then polymers: molecular weight, thermoplastics and thermosets, copolymers and crystallinity. Ceramics: the radius-ratio and electroneutrality rules for crystal structure, Schottky and Frenkel defects, and non-stoichiometry. Composites: types of reinforcement and matrix, the enhancement of modulus and strength, and the isostrain and isostress conditions. And the electronic and magnetic properties: band gap, Fermi energy, conductors, semiconductors and insulators; magnetisation and B-H curves, and ferro-, ferri-, antiferro-, para- and diamagnetism.

1. Classification of materials and chemical bonding

Engineering materials fall into metals and alloys, ceramics and glasses, polymers, and composites, with semiconductors and biomaterials often listed separately; the classes differ because their bonding differs. Ionic bonding transfers electrons from an electropositive to an electronegative atom and holds the ions by non-directional Coulomb attraction (NaCl, MgO): high melting points, hardness, brittleness, and electrical insulation in the solid. Covalent bonding shares electron pairs in directional bonds (diamond, Si, SiC, the backbone of polymers): very high hardness and melting point in network solids, low coordination numbers set by the bond angles. Metallic bonding holds positive ion cores in a sea of delocalised electrons: non-directional, which permits close packing, slip and ductility, and the free electrons give electrical and thermal conductivity and opacity. Most real bonds are mixed; Pauling’s estimate of ionic character is 1 − exp(−0.25(X_A − X_B)²) from the electronegativity difference.

Secondary (van der Waals) bonds arise between permanent or induced dipoles, and hydrogen bonds between a hydrogen attached to F, O or N and a lone pair on a neighbour. They are one to two orders of magnitude weaker than primary bonds but they hold polymer chains to one another, which is why thermoplastics soften at modest temperatures, and why cross-links (primary bonds between chains) make thermosets rigid. The bond-energy curve — potential energy against interatomic separation — explains three properties at once: the depth of the well correlates with melting point, its curvature at the minimum with the elastic modulus, and its asymmetry with the thermal expansion coefficient, so strongly bonded materials are stiff, refractory and expand little.

2. Structure of metals, alloys, ionic and covalent solids, and polymers

The common metallic structures
StructureAtoms per cellCoordination numbera in terms of RPacking factor
Simple cubic16a = 2Rπ/6 = 0.52
BCC (α-Fe, Cr, Mo, W)28a = 4R/√3 (along the body diagonal)√3π/8 = 0.68
FCC (γ-Fe, Al, Cu, Ni)412a = 2√2R (along the face diagonal)π/(3√2) = 0.74
HCP (Mg, Zn, α-Ti)612a = 2R, ideal c/a = 1.6330.74
Diamond cubic (Si, Ge, C)84a = 8R/√3√3π/16 = 0.34

The theoretical density follows from the cell: ρ = nA/(V_c N_A), with n atoms per cell of atomic mass A in a cell of volume V_c = a³ (cubic) and N_A = 6.022 × 10²³ mol⁻¹. For copper, FCC with a = 0.3615 nm and A = 63.55 g/mol, ρ = 4 × 63.55/(6.022 × 10²³ × (0.3615 × 10⁻⁷ cm)³) = 8.94 g/cm³. Miller indices (hkl) of a plane are the reciprocals of its intercepts on the axes in units of the lattice parameters, cleared of fractions: a plane cutting x at 1, y at 2 and parallel to z has reciprocals 1, ½, 0 and indices (210). Directions [uvw] are the smallest integer components of a vector; in cubic crystals [hkl] is perpendicular to (hkl). Families are written {hkl} and ⟨uvw⟩. The spacing of (hkl) planes in a cubic crystal is d = a/√(h² + k² + l²). Linear and planar densities count atoms centred on a direction or plane per unit length or area; the densest planes are {111} in FCC and {110} in BCC, and these are the slip planes.

FCC contains four octahedral interstitial sites (at the cell centre and edge midpoints) and eight tetrahedral sites per cell; BCC has larger tetrahedral sites but its octahedral sites are distorted, which is why carbon causes tetragonal distortion in ferrite and why austenite dissolves far more carbon. Alloys form substitutional solid solutions when the Hume-Rothery rules are met — atomic sizes within about 15%, the same crystal structure, similar electronegativity and similar valence — and interstitial solid solutions when the solute is small (C, N, H, B). Where they are not met, intermediate phases and intermetallic compounds form. Ionic solids are built as a lattice of the larger anions with cations in the interstices: rock salt (NaCl, MgO, FeO; cations in all octahedral sites of FCC anions), cesium chloride, zinc blende (ZnS; half the tetrahedral sites), fluorite (CaF₂, UO₂, ZrO₂) and perovskite (CaTiO₃, BaTiO₃). Covalent solids have low-coordination networks: diamond cubic for C, Si and Ge; silicates built from SiO₄⁴⁻ tetrahedra sharing corners into chains, sheets and frameworks. Polymers are long chains whose structure — linear, branched, cross-linked, network — and conformation decide their behaviour.

3. Polymers: molecular weight, thermoplastics and thermosets, copolymers, crystallinity

A polymer is a distribution of chain lengths, so its molecular weight is an average. The number-average M̄_n = Σx_iM_i weights each fraction by the number (mole) fraction x_i of chains; the weight-average M̄_w = Σw_iM_i weights by the mass fraction w_i and is always at least as large, because long chains carry more mass. Their ratio M̄_w/M̄_n, the polydispersity index, is 1 for a uniform polymer and typically 1.5-3 or more for commercial ones. The degree of polymerisation is M̄_n divided by the mer (repeat-unit) molecular weight — 28 g/mol for polyethylene’s C₂H₄. Strength, melt viscosity and softening temperature rise with molecular weight.

Thermoplastics are linear or branched chains held together by secondary bonds; they soften on heating and harden on cooling reversibly, can be remoulded and recycled, and include polyethylene, polypropylene, PVC, polystyrene, nylon and PET. Thermosets are cross-linked into a three-dimensional network of primary bonds during curing; they do not melt, decompose on strong heating, are harder, stiffer and more dimensionally stable, and include epoxies, phenol-formaldehyde (Bakelite), polyesters and vulcanised rubber in the limit. Elastomers are lightly cross-linked polymers above T_g that extend enormously and recover. Copolymers contain two kinds of mer arranged randomly, alternately, in blocks or as grafts of one on a backbone of the other: styrene-butadiene rubber is random, ABS is a graft, and block copolymers form thermoplastic elastomers. Crystallinity requires regular chains — linear rather than branched, isotactic or syndiotactic rather than atactic, with no bulky irregular side groups — and slow cooling; crystalline regions are chain-folded lamellae, often grown into spherulites, and a polymer is never fully crystalline. The percent crystallinity is found from densities: %c = ρ_c(ρ_s − ρ_a)/(ρ_s(ρ_c − ρ_a)) × 100, with ρ_s the specimen density and ρ_c and ρ_a those of the fully crystalline and fully amorphous polymer. Higher crystallinity raises density, stiffness, strength and chemical resistance.

4. Ceramics: radius ratio, electroneutrality, and point defects

In an ionic crystal each cation surrounds itself with as many anions as can touch it without the anions overlapping, so the coordination number is fixed by the radius ratio r_c/r_a; and the arrangement must be electrically neutral overall, which fixes the stoichiometry and so the fraction of interstitial sites filled. The critical ratios come from geometry: a cation just touching three anions in a triangle has r_c/r_a = 0.155, four in a tetrahedron 0.225, six in an octahedron 0.414, eight at the corners of a cube 0.732. Na⁺ (0.102 nm) and Cl⁻ (0.181 nm) have a ratio of 0.56, between 0.414 and 0.732, so NaCl is six-coordinated: rock salt. Cs⁺ is larger, the ratio exceeds 0.732, and CsCl is eight-coordinated. Pauling’s further rules (the electrostatic bond strength reaching each anion balances its charge; polyhedra prefer to share corners rather than edges or faces) explain the silicates.

Radius ratio and coordination
r_c/r_aCoordination numberGeometryExample
< 0.1552Linear—
0.155-0.2253TriangularB₂O₃
0.225-0.4144TetrahedralSiO₂, ZnS
0.414-0.7326OctahedralNaCl, MgO (rock salt)
0.732-1.08CubicCsCl, CaF₂ (fluorite)

Point defects in ionic crystals must preserve charge neutrality. A Schottky defect is a pair (for a 1:1 compound) of a cation vacancy and an anion vacancy, as in NaCl and MgO; it lowers the density. A Frenkel defect is a cation that has left its site for an interstitial position, leaving a vacancy — favoured when the cation is small and the structure has room, as in AgCl and AgBr; it leaves the density unchanged. Aliovalent impurities are compensated by vacancies too: Ca²⁺ substituting for Na⁺ in NaCl creates one Na⁺ vacancy for each Ca²⁺, and Y³⁺ in ZrO₂ creates oxygen vacancies, which is what makes yttria-stabilised zirconia an oxygen-ion conductor. Non-stoichiometric compounds depart from their ideal ratio by changing the valence of some ions. Wüstite is Fe₁₋ₓO: some iron is Fe³⁺, and each pair of Fe³⁺ ions is balanced by one iron vacancy (metal deficiency); zinc oxide heated in zinc vapour takes up excess zinc as interstitials (metal excess), becoming an n-type semiconductor. Kröger-Vink notation writes these defects with their effective charges.

5. Composites: reinforcements, matrices, isostrain and isostress

A composite combines a matrix — polymer (epoxy, polyester, thermoplastics), metal (Al, Ti, Mg) or ceramic (SiC, Al₂O₃, glass-ceramics) — with a reinforcement — particles, short (discontinuous) fibres, whiskers or continuous fibres of glass, carbon, aramid, boron, SiC or alumina — to get a property combination neither has alone: stiffness and strength with low density in polymer-matrix composites, stiffness and wear resistance in metal-matrix composites, and toughness in ceramic-matrix composites, where fibres bridge cracks. The matrix binds and protects the fibres and transfers load to them by shear at the interface; a fibre carries its full share of load only if it is longer than the critical length l_c = σ_f d/(2τ_c), where τ_c is the interfacial (or matrix) shear strength.

For continuous aligned fibres two limiting conditions bound the modulus. Loaded along the fibres, fibre and matrix strain equally (isostrain) and the loads add, so the rule of mixtures gives the upper bound E_c = V_fE_f + V_mE_m, and the fraction of the load carried by the fibres is F_f/F_c = V_fE_f/(V_fE_f + V_mE_m) — nearly all of it when E_f ≫ E_m. Loaded across the fibres, they carry equal stress (isostress) and the strains add, giving the lower bound 1/E_c = V_f/E_f + V_m/E_m, dominated by the compliant matrix. Particulate composites fall between the two bounds. The longitudinal strength of a continuous-fibre composite that fails when the fibres break is σ_c = σ_f V_f + σ′_m(1 − V_f), where σ′_m is the matrix stress at the fibre failure strain.

⚠️ Isostrain for the upper bound, isostress for the lower
The arithmetic mean V_fE_f + V_mE_m is the parallel (longitudinal, isostrain) case and the harmonic mean is the series (transverse, isostress) case. For 60% glass fibre (70 GPa) in epoxy (3 GPa) they are 43.2 and 7.0 GPa — a factor of six apart, which is why a unidirectional laminate is so weak across its fibres.

6. Electronic properties: bands, Fermi energy, conductors, semiconductors and insulators

When atoms come together in a solid their discrete energy levels broaden into bands. The occupancy of states is given by the Fermi-Dirac function f(E) = 1/(1 + exp((E − E_F)/kT)): at 0 K all states below the Fermi energy E_F are full and all above it empty, and at any temperature f(E_F) = ½. Whether a solid conducts depends on whether there are empty states immediately above the highest filled ones. In a metal the highest occupied band is partly filled, or a filled band overlaps an empty one, so electrons at E_F can be accelerated by an infinitesimal field: a conductor, with resistivity that rises with temperature because lattice vibrations scatter the electrons. In semiconductors and insulators the valence band is full and separated from the empty conduction band by a band gap E_g: small in semiconductors (Si about 1.1 eV, Ge about 0.67 eV, GaAs about 1.4 eV) and large in insulators (above roughly 4 eV; diamond about 5.5 eV).

In an intrinsic semiconductor, thermal excitation across the gap creates equal numbers of conduction electrons and holes, n = p = n_i ∝ T^(3/2) exp(−E_g/2kT), and E_F lies near mid-gap. Conductivity is σ = neμ_e + peμ_h, with the electronic charge e = 1.602 × 10⁻¹⁹ C and the mobilities μ; it rises steeply with temperature, the opposite of a metal. Doping makes it extrinsic: a group-V donor (P, As, Sb) in silicon gives an n-type semiconductor with electrons as majority carriers and E_F moved towards the conduction band; a group-III acceptor (B, Al, Ga) gives p-type, with holes and E_F moved towards the valence band. Over a wide range of temperature the extrinsic carrier concentration equals the dopant concentration (the saturation region), which is what makes doped devices stable; at high temperature intrinsic generation takes over again.

7. Magnetic properties: magnetisation, B-H curves and the five kinds of magnetism

A field H (A/m) applied to a material produces a magnetisation M (magnetic moment per unit volume, A/m), and the flux density is B = μ₀(H + M) with μ₀ = 4π × 10⁻⁷ H/m. The susceptibility χ = M/H and relative permeability μ_r = 1 + χ classify the response. Diamagnetism is a weak opposing moment induced in every material by the field acting on orbital electrons: χ is small and negative, about −10⁻⁵ (Cu, Au, Zn, water, most polymers), and a superconductor is a perfect diamagnet, χ = −1. Paramagnetism arises in atoms with unpaired electrons whose permanent moments, randomly oriented, partly align with the field: χ is small and positive, about 10⁻⁵-10⁻³ (Al, Ti, Pt, O₂), and falls with temperature. In ferromagnets (Fe, Co, Ni, Gd) exchange interaction aligns neighbouring moments parallel within domains, giving very large, non-linear magnetisation that is lost above the Curie temperature. In antiferromagnets (MnO, NiO, Cr) exchange aligns neighbouring moments antiparallel and equal, so there is no net moment below the Néel temperature. In ferrimagnets (ferrites such as Fe₃O₄ and NiFe₂O₄, garnets) the antiparallel sublattices have unequal moments and a net magnetisation remains — ferromagnet-like behaviour in an insulating oxide, which is why ferrites are used at high frequencies where eddy currents would heat a metal core.

The B-H curve of a ferromagnet starts on the initial magnetisation curve, as domains aligned with the field grow by domain-wall motion and then rotate, up to saturation. On reducing the field the flux does not retrace its path: at H = 0 a remanence B_r remains, and a reverse field equal to the coercivity H_c is needed to bring B to zero. The area of the hysteresis loop is the energy lost per cycle per unit volume. Soft magnetic materials (Fe-Si electrical steel, permalloy Ni-Fe, soft ferrites, amorphous Fe-B-Si) have low coercivity, high permeability and a thin loop, for transformer and motor cores; they are made soft by removing whatever pins domain walls — impurities, inclusions, fine grains, internal stress. Hard magnetic materials (alnico, hard ferrites, Sm-Co, Nd-Fe-B) have high coercivity, high remanence and a large (BH)_max, for permanent magnets; they are made hard by pinning walls or by using single-domain particles. In Fe₃O₄ the Fe³⁺ ions on the two sublattices cancel and the net moment per formula unit is that of Fe²⁺, 4 Bohr magnetons (μ_B = 9.274 × 10⁻²⁴ A m²).

Key takeaways

  • APF: SC 0.52, BCC 0.68 (a = 4R/√3), FCC and HCP 0.74 (a = 2√2R), diamond 0.34. ρ = nA/(a³N_A); d = a/√(h² + k² + l²); Miller indices are reciprocals of intercepts.
  • M̄_n = Σx_iM_i ≤ M̄_w = Σw_iM_i; thermoplastics soften reversibly, thermosets are cross-linked; %crystallinity = ρ_c(ρ_s − ρ_a)/(ρ_s(ρ_c − ρ_a)) × 100.
  • Radius ratio 0.155, 0.225, 0.414, 0.732 separate CN 2, 3, 4, 6, 8. Schottky = cation + anion vacancy pair (lowers density); Frenkel = vacancy + interstitial (density unchanged); Fe₁₋ₓO balances two Fe³⁺ with one vacancy.
  • Isostrain (upper bound) E_c = V_fE_f + V_mE_m; isostress (lower bound) 1/E_c = V_f/E_f + V_m/E_m; fibres must exceed l_c = σ_f d/(2τ_c).
  • f(E) = 1/(1 + exp((E − E_F)/kT)); σ = neμ_e + peμ_h; metals’ resistivity rises and semiconductors’ falls with T. Dia (χ ≈ −10⁻⁵), para (small +), ferro (Fe, Co, Ni), antiferro (MnO), ferri (Fe₃O₄, 4 μ_B per formula unit); soft magnets have thin loops, hard magnets high H_c.

Practice questions (18)

Attempt each one before opening the answer. Every explanation names the tempting wrong option as well as the right one, because that is where marks are lost.

  1. Which type of primary bond is non-directional and leaves electrons free to move, allowing close packing, slip and electrical conduction?

    1. Metallic
    2. Covalent
    3. Ionic
    4. Hydrogen bonding
    Show answer

    Answer: A — Metallic

    Metallic bonding holds ion cores in a sea of delocalised electrons; being non-directional it allows close-packed structures and dislocation glide, and the free electrons conduct. Covalent bonds are directional and localised; ionic bonds are non-directional but the electrons are bound to the anions, so ionic solids insulate and slip is restricted by like-charge repulsion; hydrogen bonds are secondary bonds.
  2. What is the atomic packing factor of the body-centred cubic structure (to two decimal places)?

    Numerical answer — type the value.

    Show answer

    Answer: 0.68

    Two atoms per cell touch along the body diagonal, so a√3 = 4R and a = 4R/√3. APF = 2 × (4/3)πR³/a³ = (8/3)πR³ × 3√3/(64R³) = √3π/8 = 0.680. FCC’s 0.74 comes from four atoms and a = 2√2R; taking the atoms as touching along the cube edge (a = 2R) gives an impossible 1.05.
  3. Copper is FCC with a lattice parameter of 0.3615 nm and an atomic mass of 63.55 g/mol. What is its theoretical density, in g/cm³ (to two decimal places)? Take N_A = 6.022 × 10²³ mol⁻¹.

    Numerical answer — type the value.

    Show answer

    Answer: 8.94

    ρ = nA/(a³N_A) with n = 4: a³ = (0.3615 × 10⁻⁷ cm)³ = 4.724 × 10⁻²³ cm³, so ρ = 4 × 63.55/(4.724 × 10⁻²³ × 6.022 × 10²³) = 254.2/28.45 = 8.94 g/cm³, matching the measured density of copper. Using n = 2 (BCC) halves it to 4.47; leaving a in nm without converting to cm is off by 10²¹.
  4. α-iron is BCC with a density of 7.87 g/cm³ and an atomic mass of 55.85 g/mol. What is its lattice parameter, in nm (to three decimal places)? Take N_A = 6.022 × 10²³ mol⁻¹.

    Numerical answer — type the value.

    Show answer

    Answer: 0.287

    a³ = nA/(ρN_A) = 2 × 55.85/(7.87 × 6.022 × 10²³) = 111.7/4.739 × 10²⁴ = 2.357 × 10⁻²³ cm³, so a = 2.867 × 10⁻⁸ cm = 0.287 nm. Check forwards: 2 × 55.85/((2.867 × 10⁻⁸)³ × 6.022 × 10²³) = 111.7/14.19 = 7.87 g/cm³. Using n = 4 gives 0.361 nm, close to the lattice parameter of austenite — the right number for the wrong phase.
  5. A cubic crystal has a lattice parameter of 0.36 nm. What is the interplanar spacing of its (220) planes, in nm (to three decimal places)?

    Numerical answer — type the value.

    Show answer

    Answer: 0.127

    d = a/√(h² + k² + l²) = 0.36/√(4 + 4 + 0) = 0.36/2.828 = 0.127 nm. It is half the (110) spacing, 0.255 nm, as (220) is the second-order reflection from (110) planes. Dividing by 8 instead of √8 gives 0.045 nm.
  6. A plane intercepts the crystal axes at x = 1, y = 2 (in units of the lattice parameters) and is parallel to z. Its Miller indices are:

    1. (210)
    2. (120)
    3. (12∞)
    4. (201)
    Show answer

    Answer: A — (210)

    Take reciprocals of the intercepts: 1/1, 1/2, 1/∞ = 1, ½, 0; clear the fraction by multiplying by 2 to get (210). Writing the intercepts themselves gives (120), and ∞ is never a Miller index — a plane parallel to an axis has index 0 for it.
  7. A polymer sample contains three fractions: number fraction 0.2 with molecular weight 10 000 g/mol, 0.5 with 20 000 g/mol and 0.3 with 40 000 g/mol. What is its weight-average molecular weight, in g/mol (to the nearest whole number)?

    Numerical answer — type the value.

    Show answer

    Answer: 29167

    M̄_n = Σx_iM_i = 2000 + 10 000 + 12 000 = 24 000 g/mol. Weight fractions w_i = x_iM_i/M̄_n = 0.0833, 0.4167, 0.5000, so M̄_w = Σw_iM_i = 833 + 8333 + 20 000 = 29 167 g/mol. Directly, M̄_w = Σx_iM_i²/Σx_iM_i = (2 × 10⁷ + 2 × 10⁸ + 4.8 × 10⁸)/24 000 = 7 × 10⁸/24 000 = 29 167. The polydispersity is 1.22. Stopping at the number average gives 24 000, which is M̄_n, not M̄_w.
  8. A polyethylene specimen has a density of 0.94 g/cm³. The densities of fully crystalline and fully amorphous polyethylene are taken as 1.00 and 0.85 g/cm³. What is its percent crystallinity (to one decimal place)?

    Numerical answer — type the value.

    Show answer

    Answer: 63.8

    %c = ρ_c(ρ_s − ρ_a)/(ρ_s(ρ_c − ρ_a)) × 100 = 1.00 × 0.09/(0.94 × 0.15) × 100 = 0.09/0.141 × 100 = 63.8%. This is a MASS fraction; the volume fraction crystalline is (ρ_s − ρ_a)/(ρ_c − ρ_a) = 0.09/0.15 = 60%, and quoting that is the usual slip.
  9. Which of the following statements about polymers are correct?

    1. Thermosetting polymers are cross-linked and do not soften reversibly on reheating
    2. The weight-average molecular weight is always greater than or equal to the number-average
    3. Atactic polymers crystallise more readily than isotactic ones
    4. ABS is an example of a graft copolymer
    Show answer

    Answer: A — Thermosetting polymers are cross-linked and do not soften reversibly on reheating; B — The weight-average molecular weight is always greater than or equal to the number-average; D — ABS is an example of a graft copolymer

    Cross-links of primary bonds stop thermosets from flowing on reheating (A). M̄_w weights each chain by its mass, so it is never below M̄_n, with equality only for a uniform polymer (B). ABS has styrene-acrylonitrile chains grafted on a polybutadiene backbone (D). C is reversed: the random side-group placement of an atactic chain prevents regular packing, so isotactic and syndiotactic polymers crystallise and atactic ones are largely amorphous.
  10. The ionic radii of Na⁺ and Cl⁻ are 0.102 nm and 0.181 nm. What coordination number does the radius-ratio rule predict for Na⁺ in NaCl?

    Numerical answer — type the value.

    Show answer

    Answer: 6

    r_c/r_a = 0.102/0.181 = 0.564, which lies between 0.414 and 0.732, the range for octahedral (six-fold) coordination — the rock-salt structure NaCl actually has. Inverting the ratio (1.77) and reading it as above 0.732 gives the eight-fold CsCl answer, the common slip.
  11. Wüstite has the composition Fe₀.₉₅O, with charge neutrality maintained by Fe³⁺ ions and iron vacancies. What fraction of the iron ions are Fe³⁺ (to three decimal places)?

    Numerical answer — type the value.

    Show answer

    Answer: 0.105

    Let y be Fe³⁺ per formula unit; then 0.95 − y are Fe²⁺. Neutrality with one O²⁻: 3y + 2(0.95 − y) = 2, so y = 0.10. The fraction of iron that is Fe³⁺ is 0.10/0.95 = 0.105. Check: 0.05 vacancies per O, and two Fe³⁺ per vacancy gives 0.10 Fe³⁺. Reporting 0.10 answers per formula unit, not per iron ion.
  12. A Frenkel defect in an ionic crystal such as AgCl consists of:

    1. A cation vacancy and a cation interstitial
    2. A cation vacancy and an anion vacancy
    3. An anion interstitial and a cation interstitial
    4. A substitutional impurity of higher valence
    Show answer

    Answer: A — A cation vacancy and a cation interstitial

    A Frenkel defect is a cation displaced from its site into an interstice, leaving a vacancy behind — easy in AgCl because Ag⁺ is small; the number of ions is unchanged, so the density is too. A cation-anion vacancy pair is a Schottky defect (NaCl, MgO); an aliovalent impurity is compensated by vacancies but is not itself a Frenkel defect.
  13. A unidirectional composite contains 60 vol% glass fibres (E = 70 GPa) in epoxy (E = 3 GPa). What is its longitudinal (isostrain) modulus, in GPa (to one decimal place)?

    Numerical answer — type the value.

    Show answer

    Answer: 43.2

    Isostrain rule of mixtures: E_c = V_fE_f + V_mE_m = 0.6 × 70 + 0.4 × 3 = 42 + 1.2 = 43.2 GPa. The fibres carry 42/43.2 = 97% of the load. The isostress (transverse) value, 1/(0.6/70 + 0.4/3) = 7.0 GPa, is the lower bound for the same composite.
  14. For the same composite (60 vol% glass fibres, E = 70 GPa, in epoxy, E = 3 GPa), what is the transverse (isostress) modulus, in GPa (to two decimal places)?

    Numerical answer — type the value.

    Show answer

    Answer: 7.05

    Isostress: 1/E_c = V_f/E_f + V_m/E_m = 0.6/70 + 0.4/3 = 0.00857 + 0.13333 = 0.14190 GPa⁻¹, so E_c = 7.05 GPa. Equivalently E_c = E_fE_m/(V_fE_m + V_mE_f) = 210/(1.8 + 28) = 210/29.8 = 7.05 GPa. The matrix term dominates; averaging the moduli arithmetically gives the longitudinal 43.2 GPa instead.
  15. At 300 K, what is the probability that an electron state lying 0.1 eV above the Fermi energy is occupied (to three decimal places)? Take k = 8.617 × 10⁻⁵ eV/K.

    Numerical answer — type the value.

    Show answer

    Answer: 0.020

    kT = 8.617 × 10⁻⁵ × 300 = 0.02585 eV, so (E − E_F)/kT = 0.1/0.02585 = 3.868 and f = 1/(1 + e^3.868) = 1/(1 + 47.85) = 0.0205. The Boltzmann approximation e^(−3.868) = 0.0209 is close, as it should be several kT above E_F. A state 0.1 eV BELOW E_F has f = 1 − 0.0205 = 0.980.
  16. An n-type semiconductor has 1 × 10²² conduction electrons per m³ with a mobility of 0.14 m²/(V s); holes are negligible. What is its conductivity, in S/m (to one decimal place)? Take e = 1.602 × 10⁻¹⁹ C.

    Numerical answer — type the value.

    Show answer

    Answer: 224.3

    σ = neμ_e = 1 × 10²² × 1.602 × 10⁻¹⁹ × 0.14 = 1602 × 0.14 = 224.3 S/m, a resistivity of 4.46 × 10⁻³ Ω m. Units: m⁻³ × C × m²/(V s) = C/(V m s) = S/m. Using the hole mobility of silicon (a few times smaller) would understate it.
  17. Which of the following pairings of a material with its type of magnetism at room temperature are correct?

    1. Fe₃O₄ — ferrimagnetic
    2. MnO — antiferromagnetic (below its Néel temperature)
    3. Copper — paramagnetic
    4. Aluminium — paramagnetic
    Show answer

    Answer: A — Fe₃O₄ — ferrimagnetic; B — MnO — antiferromagnetic (below its Néel temperature); D — Aluminium — paramagnetic

    Magnetite has unequal antiparallel sublattices — ferrimagnetic (A). MnO orders antiparallel with equal moments below its Néel temperature — antiferromagnetic (B). Aluminium has a small positive susceptibility — paramagnetic (D). Copper is diamagnetic, with χ ≈ −10⁻⁵, because its filled d shell leaves no permanent moment, so C is wrong.
  18. Magnetite, Fe₃O₄, has a cubic unit cell of edge 0.839 nm containing 8 formula units, and a net moment of 4 Bohr magnetons per formula unit. What is its saturation magnetisation, in units of 10⁵ A/m (to two decimal places)? Take μ_B = 9.274 × 10⁻²⁴ A m².

    Numerical answer — type the value.

    Show answer

    Answer: 5.02

    Moment per cell = 8 × 4 × 9.274 × 10⁻²⁴ = 2.968 × 10⁻²² A m²; cell volume = (0.839 × 10⁻⁹)³ = 5.906 × 10⁻²⁸ m³. M_s = 2.968 × 10⁻²²/5.906 × 10⁻²⁸ = 5.02 × 10⁵ A/m. The Fe³⁺ ions (5 μ_B each) on the two sublattices cancel and only the Fe²⁺ moment survives; counting all three iron ions as parallel (14 μ_B) gives 17.6 × 10⁵ A/m.