Resource Geology: Ores and Their Genesis, Fluid Inclusions, Coal and Petroleum, Marine Resources, Exploration and Reserve Estimation, and Indian Resources
2. Ore-forming processes
| Process | How the metal is concentrated | Examples |
|---|---|---|
| Magmatic | Early crystallisation and settling (chromite, magnetite layers); unmixing of a sulphide melt from silicate magma (Ni–Cu–PGE sulphides); residual melts (pegmatite, carbonatite); kimberlite carries diamond | Chromite in ultramafic rock; Ni–Cu sulphide; diamond pipes |
| Hydrothermal | Hot aqueous fluids carry metals as chloride or bisulphide complexes and deposit them on cooling, boiling, mixing or reaction with wall rock | Porphyry Cu–Mo, skarn, epithermal Au–Ag, lode gold, volcanogenic massive sulphide, Mississippi Valley-type Pb–Zn |
| Sedimentary | Chemical precipitation (banded iron formation, sedimentary manganese, phosphorite, evaporite) and mechanical sorting of heavy minerals (placers) | Precambrian iron formations, beach-sand placers, Witwatersrand paleoplacer |
| Supergene | Weathering: residual enrichment (bauxite, nickel laterite) and enrichment of sulphides below the water table by copper leached from above | Bauxite; chalcocite blanket beneath a gossan |
| Metamorphogenic | Metamorphism forms industrial minerals and remobilises older ore into hinges and shears; metamorphic fluids deposit lode gold | Graphite, kyanite–sillimanite, garnet; remobilised sulphides |
Hydrothermal deposition has four triggers: a fall in temperature; boiling, which strips H₂S and CO₂ into a vapour phase; mixing with cooler or oxidised water; and reaction with wall rock (neutralisation, sulphidation of iron-bearing minerals). In a porphyry system alteration zones run outward from the intrusion as potassic, phyllic (quartz–sericite–pyrite), argillic and propylitic, and copper is concentrated in the inner potassic–phyllic zones.
3. Fluid inclusions in ore genesis
A fluid inclusion is a droplet of ore fluid trapped in a crystal. Primary inclusions form along growth zones, secondary inclusions along fractures healed after growth, and pseudosecondary inclusions along fractures healed during growth; only primary and pseudosecondary ones date the ore fluid. At room temperature an inclusion shows liquid, a vapour bubble and sometimes a halite daughter crystal (salinity above about 26 wt% NaCl) or liquid CO₂.
Heating gives the homogenisation temperature Th (the bubble vanishes), a minimum trapping temperature that needs a pressure correction unless the fluid was boiling. Freezing gives the first-melting temperature (about −21 °C for H₂O–NaCl, which identifies the salt system) and the final ice-melting temperature Tm. With θ = −Tm in °C, the salinity in wt% NaCl equivalent is S = 1.78θ − 0.0442θ² + 0.000557θ³ (Bodnar, valid up to the eutectic θ = 21.2 °C, S = 23.2). Example: Tm = −5.0 °C gives S = 8.90 − 1.11 + 0.07 = 7.86 wt%.
- Porphyry Cu–Mo: about 300 to 600 °C, brines of tens of wt% NaCl equivalent beside vapour-rich inclusions (boiling).
- Orogenic (lode) gold: about 250 to 400 °C, low salinity (a few wt% NaCl equivalent), H₂O–CO₂ fluid.
- Epithermal Au–Ag: about 150 to 300 °C, low salinity, often boiling.
- Mississippi Valley-type Pb–Zn: about 80 to 200 °C, saline basinal brines.
4. Coal geology
Coal forms from plant debris preserved in waterlogged peat and then coalified by burial: rank rises with temperature, not time alone, through peat, lignite, sub-bituminous, bituminous and anthracite, as carbon increases and moisture and volatile matter fall. Macerals are the microscopic constituents: vitrinite (woody tissue), liptinite (spores, resin, cuticle, algae; hydrogen-rich) and inertinite (charred or oxidised matter). Lithotypes are the visible bands: vitrain, clarain, durain and fusain. Vitrinite reflectance R₀ rises with rank and measures thermal maturity.
Proximate analysis gives moisture M, volatile matter VM, ash A and fixed carbon FC in percent, with FC = 100 − (M + VM + A) on the as-received basis; ultimate analysis gives C, H, N, S and O. The fuel ratio is FC / VM. Example: M = 8%, VM = 28% and A = 24% give FC = 100 − 60 = 40% and a fuel ratio of 40 / 28 = 1.43. Coking coal needs low ash and sulphur and good caking behaviour.
5. Petroleum geology
A petroleum system needs a source rock, a reservoir, a seal, a trap and correct timing, meaning that the trap existed before the oil migrated. Source rocks are fine-grained and organic-rich (TOC of about 0.5 wt% or more). The kerogen type sets the product: Type I (algal, lacustrine; hydrogen-rich, oil), Type II (marine; oil and gas) and Type III (terrestrial plants; low H/C, mainly gas). Burial heating runs through diagenesis (biogenic methane), catagenesis (the oil window, roughly 60 to 120 °C or vitrinite reflectance of about 0.6 to 1.3%, with wet gas at its base) and metagenesis (dry gas).
Reservoirs are porous, permeable sandstones and carbonates; seals are shale or evaporite; traps are structural (anticline, fault), stratigraphic (pinch-out, unconformity, reef) or combined. Oil leaves the source rock by primary migration and moves up carrier beds by secondary migration, floating on water, until a seal stops it; in a filled trap gas lies over oil over water. Unconventional resources include coalbed methane, shale gas and gas hydrates. With a surface temperature of 25 °C and a gradient of 30 °C/km, the oil window (60 to 120 °C) lies between (60 − 25) / 30 = 1.2 km and (120 − 25) / 30 = 3.2 km.
6. Marine mineral resources
Marine resources lie inside a country’s Exclusive Economic Zone (to 200 nautical miles) or in the international Area beyond national jurisdiction, which the International Seabed Authority regulates. The main kinds are these.
- Polymetallic nodules: Mn–Fe oxide concretions on abyssal plains carrying Ni, Cu and Co; they grow very slowly, by millimetres per million years. India holds an exploration contract for them in the Central Indian Ocean Basin.
- Cobalt-rich ferromanganese crusts coat seamounts, and seafloor massive sulphides form at hydrothermal vents on spreading ridges and in back-arc basins.
- Nearshore deposits: placers of ilmenite, rutile, zircon, monazite and garnet, shelf phosphorites, and sand, gravel and lime mud.
- Gas hydrates in continental-margin sediment are a potential fuel.
7. Prospecting, sampling, reserve estimation, geostatistics and mining
Exploration narrows the search in stages: regional reconnaissance (geological mapping, stream-sediment geochemistry, remote sensing, airborne geophysics), target testing (soil geochemistry, ground geophysics, trenching) and then drilling (diamond core, reverse circulation) to outline the body. Sampling must be unbiased: channel or chip samples across a face, split drill core, bulk samples for erratic ore. Safe sample weight rises with the square of the largest particle size (Richards–Czeczott, Q = kd²), and a high-nugget ore such as gold needs larger or more samples.
Resources are occurrences with reasonable prospects of economic extraction, graded inferred, indicated and measured; reserves are the economically mineable part, graded probable and proved. Tonnage = volume × bulk density, with the tonnage factor 1 / density in m³ per tonne, and metal content = tonnage × grade. Grade over several intersections is weighted, not a plain mean: 2 m at 4%, 6 m at 1% and 2 m at 3% give (8 + 6 + 6) / 10 = 2.0%. Example: 200 m × 50 m × 20 m = 200,000 m³ at 3.2 t/m³ is 640,000 t, which holds 16,000 t Cu at 2.5% Cu. Methods are cross-section, polygon, triangle, inverse-distance weighting and kriging.
Cut-off grade is the grade below which material does not pay for its mining and processing: cut-off = cost per tonne ÷ (price per unit of metal × recovery). Raising it lowers the tonnage and raises the average grade (the grade–tonnage curve). Example: $48 per tonne, $60 per gram and 80% recovery give 48 / (60 × 0.8) = 1.0 g/t. In an open pit the stripping ratio is waste ÷ ore, and the pit deepens until it reaches the break-even ratio at which an ore tonne just pays to remove its waste. Underground methods suit deep, steep or narrow bodies: room and pillar, cut-and-fill, shrinkage and sublevel stoping, block caving, and longwall for coal.
Geostatistics treats grade as a regionalised variable that becomes less alike as the separation h grows. The experimental semivariogram is γ(h) = [1 / 2N(h)] Σ [z(xᵢ) − z(xᵢ + h)]². It rises from the nugget (variance at near-zero lag: measurement error and micro-scale variability) to the sill (total variance) at the range, beyond which samples are uncorrelated. Ordinary kriging estimates a point or block as a weighted sum of nearby samples whose weights sum to 1 and minimise the estimation variance, which it also reports. Example: grades 2, 4, 3, 5, 6 at 1 m spacing give squared differences 4, 1, 4, 1 at lag 1 m, so γ(1) = 10 / (2 × 4) = 1.25. For samples at 0 m and 10 m, a linear variogram with no nugget and an estimate at 2.5 m, the kriging weights are 0.75 and 0.25.
8. Strategic, essential and critical minerals and fuels of India
Strategic minerals matter for defence and nuclear security (uranium, thorium, beryllium, rare earths); essential minerals are those industry needs in bulk (iron ore, coal, limestone); critical minerals combine high economic importance with supply risk (lithium, cobalt, nickel, graphite, rare earth elements are on the official list). The labels describe use and supply, not geology, and one mineral may carry several. The table gives widely known occurrences only.
| Resource | Main occurrences |
|---|---|
| Iron ore (hematite, magnetite) | Banded iron formations of Odisha–Jharkhand, Chhattisgarh (Bailadila), Karnataka, Goa |
| Manganese | Odisha; Madhya Pradesh–Maharashtra (Balaghat–Nagpur belt); Karnataka |
| Chromite | Sukinda ultramafic belt, Odisha, the bulk of Indian resources |
| Bauxite | Odisha (largest), Gujarat, Jharkhand, Maharashtra, Chhattisgarh |
| Copper | Khetri (Rajasthan), Malanjkhand (Madhya Pradesh), Singhbhum (Jharkhand) |
| Lead–zinc | Rajasthan: Zawar, Rampura Agucha, Rajpura–Dariba |
| Gold | Karnataka (Hutti; Kolar field now closed), Andhra Pradesh (Ramagiri) |
| Uranium | Jaduguda (Singhbhum, Jharkhand), Tummalapalle (Andhra Pradesh), Domiasiat (Meghalaya) |
| Beach-sand minerals (ilmenite, rutile, zircon, monazite, garnet) | Coasts of Kerala, Tamil Nadu, Odisha and Andhra Pradesh; monazite is the thorium source |
| Diamond | Panna, Madhya Pradesh |
| Coal | Mostly Permian Gondwana coal (Damodar, Son, Mahanadi, Godavari valleys) with high ash; Jharia has prime coking coal; Tertiary coal in Assam and Meghalaya; lignite at Neyveli (Tamil Nadu), Rajasthan and Gujarat |
| Petroleum and gas | Mumbai Offshore (Bombay High), Assam (Digboi), Cambay (Gujarat), Krishna–Godavari, Cauvery, Rajasthan (Barmer) |
Key takeaways
- Metal in a mineral = (atomic mass × atoms) ÷ formula mass; chalcopyrite 35% Cu, galena 87% Pb. Ore microscopy uses reflectance, colour, isotropism, hardness and cleavage; textures such as exsolution and replacement give the paragenetic sequence.
- Magmatic, hydrothermal, sedimentary, supergene and metamorphogenic processes concentrate metals; hydrothermal ore drops out on cooling, boiling, mixing or wall-rock reaction. The supergene blanket lies below the water table, under the leached gossan.
- Th is a minimum trapping temperature unless the fluid boiled. Salinity from final ice melting: S = 1.78θ − 0.0442θ² + 0.000557θ³ wt% NaCl equivalent. Porphyry fluids are hot brines, orogenic gold fluids low-salinity H₂O–CO₂, MVT fluids cool basinal brines.
- Coal rank rises from peat to anthracite; FC = 100 − (M + VM + A) and fuel ratio = FC / VM. Petroleum needs source, reservoir, seal, trap and timing; Type III kerogen is gas-prone; the oil window is about 60 to 120 °C. Nodules, crusts, sulphides, placers and hydrates are the marine resources.
- Tonnage = volume × density, grade is weighted by thickness, cut-off = cost ÷ (price × recovery), and the stripping ratio is waste ÷ ore. A semivariogram has nugget, sill and range; kriging weights sum to 1 and give an estimation variance.
- India: Sukinda chromite, Odisha bauxite and iron, Khetri and Malanjkhand copper, Rajasthan lead–zinc, Hutti gold, Jaduguda uranium, Panna diamond, beach-sand monazite, Gondwana coal (Jharia coking coal), Neyveli lignite and Mumbai Offshore, Assam, Cambay and Krishna–Godavari hydrocarbons.
Practice questions (18)
Attempt each one before opening the answer. Every explanation names the tempting wrong option as well as the right one, because that is where marks are lost.
Use atomic masses Cu 63.5, Fe 55.8, S 32.1, C 12.0, O 16.0 and H 1.0. Which of the following ore minerals contains the highest percentage of copper by weight?
Show answer
Answer: C — Chalcocite, Cu₂S
Cu percentages: chalcopyrite 63.5 / 183.5 = 34.6%; bornite 317.5 / 501.7 = 63.3%; chalcocite 127.0 / 159.1 = 79.8%; malachite 127.0 / 221.0 = 57.5%. Chalcocite is the richest copper mineral. Bornite is the tempting second, because it is copper-rich, and chalcopyrite is the most common copper mineral but has the lowest copper content here because iron and sulphur make up most of its mass.In a polished section examined in reflected light, a soft grain is white, stays dark when the stage is rotated between crossed polars, and shows triangular pits where cleavage fragments were plucked out during polishing. Which mineral is it most likely to be?
Show answer
Answer: A — Galena, PbS, which is white, isotropic and soft, with perfect cubic cleavage
A white, soft, isotropic mineral with triangular cleavage pits is galena, whose perfect cubic cleavage leaves those pits when fragments pluck out. Pyrite is also isotropic and is the tempting alternative, but it is pale yellow, very hard and has no cleavage pits. Chalcopyrite is a deeper yellow and weakly anisotropic, and hematite is strongly anisotropic with red internal reflections.In a copper deposit, secondary chalcocite and covellite form a zone below the water table, beneath a leached, iron-oxide-rich cap. Which process formed the chalcocite zone?
Show answer
Answer: D — Supergene enrichment, in which copper leached from the oxidised zone was redeposited as secondary sulphides
Chalcocite and covellite below the water table and under a leached gossan are the signature of supergene sulphide enrichment: copper dissolved by oxidation above the water table moves down and replaces primary sulphides below it. Magmatic settling, hydrothermal boiling and metamorphic remobilisation would not produce a blanket whose position is tied to the water table and to an overlying leached cap.A quartz vein hosts gold deposited as an ascending fluid boiled and lost H₂S and CO₂ to a vapour phase. Why does boiling precipitate gold that was carried as the bisulphide complex Au(HS)₂⁻?
Show answer
Answer: B — Loss of H₂S to the vapour phase removes the sulphur that keeps gold dissolved, so the complex breaks down
In gold-bearing fluids much gold travels as Au(HS)₂⁻, so it depends on dissolved reduced sulphur. Boiling partitions H₂S and CO₂ into the vapour, which destabilises the bisulphide complex and deposits gold. Boiling is also accompanied by heat loss, so the liquid cools rather than heats, the fluid does not take in atmospheric oxygen at depth, and the loss of vapour does not create a more soluble chloride complex.A primary two-phase aqueous inclusion in quartz homogenises to liquid at 240 °C. Which statement about this temperature is correct?
Show answer
Answer: A — It is a minimum trapping temperature; the true value is higher by a pressure correction unless the fluid was boiling
A fluid trapped under pressure is a single phase, and on cooling at nearly constant volume it unmixes into liquid and vapour. On heating, the bubble disappears at Th, which is therefore the minimum trapping temperature; a pressure correction raises it unless the fluid was boiling, when Th is the trapping temperature. The final ice-melting temperature, measured on freezing, gives salinity, and Th is not a maximum.A source rock is rich in woody debris of land plants, with abundant vitrinite and a low atomic H/C ratio. Which kerogen type and main product does it indicate?
Show answer
Answer: C — Type III kerogen, which is mainly gas-prone because it is hydrogen-poor
Terrestrial higher-plant material is vitrinite-rich and hydrogen-poor, which is Type III kerogen, and it generates mainly gas and little oil. Types I and II are hydrogen-rich, from algal and marine organic matter, and give oil. The option that calls woody debris a Type I source repeats the Type I error by assuming that woody tissue is hydrogen-rich, which it is not.A well on a large, sealed anticline with a good sandstone reservoir finds only water, although a mature source rock lies beside the structure. Burial-history modelling shows that the anticline formed after the main phase of oil expulsion had ended. Which is the best explanation of the dry well?
Show answer
Answer: D — The trap formed too late: the oil had already migrated elsewhere before the structure existed
A petroleum system works only if the trap exists before or during migration. The source rock is mature and the structure is large and sealed, so the best explanation is a timing failure: the oil migrated before the anticline formed and bypassed it. The stem excludes the other causes, since a mature source rock is present and the structure is described as sealed, and a high porosity does not drain oil from a sealed trap.Which pairing of a resource and its Indian occurrence is correct?
Show answer
Answer: B — Zinc and lead, mined at Rampura Agucha in Rajasthan
Rampura Agucha in Rajasthan is a major zinc–lead mine. Chromite is concentrated in the Sukinda belt of Odisha, whereas Khetri is a copper belt. Prime coking coal is associated with Jharia, while Neyveli is a lignite field. Diamond is associated with Panna in Madhya Pradesh, and the Bailadila range is known for iron ore.Which statement about polymetallic nodules is correct?
Show answer
Answer: C — They are slowly growing Mn–Fe oxide concretions on abyssal plains, rich in Ni, Cu and Co
Polymetallic nodules are Mn–Fe oxide concretions that grow by millimetres per million years on abyssal plains and carry Ni, Cu and Co. Hydrothermal precipitates at ridge vents are seafloor massive sulphides, not nodules. Nodules are oxide, not sulphide, and they occur on the deep sea floor largely beyond the EEZ, in the international Area regulated by the International Seabed Authority.Which of the following statements about ore-forming processes are correct?
Show answer
Answer: A — In a porphyry system the alteration zones run outward from the intrusion as potassic, phyllic, argillic and propylitic; B — Banded iron formations are mostly Archaean to Paleoproterozoic chemical sediments; D — Beach placers of ilmenite and monazite form by mechanical concentration of heavy minerals
Porphyry alteration is zoned from a potassic core outward through phyllic and argillic to propylitic. Banded iron formations are mostly Archaean to Paleoproterozoic chemical sediments, and beach placers are heavy-mineral concentrations made by waves and currents. Supergene enrichment occurs below the water table, because copper dissolved in the oxidised zone above is redeposited beneath it, so the statement that places it above is wrong.Which of the following statements about fluid inclusions are correct?
Show answer
Answer: B — A halite daughter crystal in an inclusion at room temperature shows a salinity above about 26 wt% NaCl; D — Vapour-rich and brine inclusions trapped together that homogenise at the same temperature indicate boiling
Halite saturation in H₂O–NaCl is near 26 wt% NaCl at room temperature, so a halite daughter crystal means a more saline fluid. Coexisting vapour-rich and brine inclusions with the same Th are the standard evidence for boiling. Secondary inclusions record later fluids, not the one present during growth, and a more negative Tm means a larger freezing-point depression and therefore a higher salinity, so those two statements are wrong.Which of the following statements about reserve estimation and geostatistics are correct?
Show answer
Answer: A — Raising the cut-off grade lowers the tonnage and raises the average grade of the ore above the cut-off; D — Kriging gives an estimation variance, which simple inverse-distance weighting does not give
Raising the cut-off removes low-grade material, so tonnage falls and the mean grade of what remains rises. Kriging yields an estimation variance together with the estimate, which inverse-distance weighting cannot. Ordinary kriging weights are constrained to sum to 1 for unbiasedness, and the nugget is the variance at near-zero lag, not at the range, so those two statements are wrong.Which of the following statements about the distribution of mineral and fuel resources in India are correct?
Show answer
Answer: A — Sukinda in Odisha is the principal chromite-bearing ultramafic belt of India; C — Jharia in Jharkhand is noted for prime coking coal of Permian Gondwana age
Sukinda holds most Indian chromite, and Jharia in the Damodar valley is the source of prime coking coal from the Permian Gondwana measures. Indian bauxite is concentrated in Odisha and neighbouring peninsular states, not in the Himalaya, and Khetri is a copper belt, not a tin province.A tabular copper ore body has a mean thickness of 12 m over a plan area of 25,000 m². The ore has a bulk density of 3.0 t/m³ and a grade of 2.4% Cu by weight, and 90% of the ore is recovered in mining. The mass of copper in the recovered ore is ____ tonnes.
Numerical answer — type the value.
Show answer
Answer: 19440
Volume = 12 × 25,000 = 300,000 m³. Ore tonnage = 300,000 × 3.0 = 900,000 t. Copper in place = 900,000 × 0.024 = 21,600 t. With 90% recovered, the copper in the recovered ore is 21,600 × 0.90 = 19,440 t. Forgetting the recovery gives 21,600, and forgetting the density gives 7,200.The cost of mining and processing is $30 per tonne of ore, the price of copper is $8,000 per tonne of metal and the metallurgical recovery is 85%. Using cut-off grade = cost per tonne of ore ÷ (price per tonne of metal × recovery), the cut-off grade is ____ % Cu (give the answer to two decimal places).
Numerical answer — type the value.
Show answer
Answer: 0.44
The metal that must be recovered from each tonne of ore to cover the cost is 30 / 8,000 = 0.00375 t per tonne of ore if recovery were complete. With 85% recovery the grade must be 0.00375 / 0.85 = 0.004412, that is a fraction by weight, and as a percentage this is 0.44% Cu. Omitting the recovery gives 0.375%, and forgetting to convert the fraction to a percentage is another slip.Two samples lie on a line, one at 0 m with a grade of 8 g/t and one at 10 m with a grade of 3 g/t. The semivariogram is linear, γ(h) = 0.5h with no nugget. Using ordinary kriging, the estimated grade at the point 4 m from the sample at 0 m is ____ g/t.
Numerical answer — type the value.
Show answer
Answer: 6
The ordinary kriging equations are λ₁γ(0) + λ₂γ(10) + μ = γ(4) and λ₁γ(10) + λ₂γ(0) + μ = γ(6), with λ₁ + λ₂ = 1. With γ(h) = 0.5h these become 5λ₂ + μ = 2 and 5λ₁ + μ = 3. Subtracting gives 5(λ₁ − λ₂) = 1, so λ₁ − λ₂ = 0.2, and with λ₁ + λ₂ = 1 the weights are λ₁ = 0.6 and λ₂ = 0.4. The estimate is 0.6 × 8 + 0.4 × 3 = 4.8 + 1.2 = 6.0 g/t. Using inverse-squared-distance or equal weights gives other values.In an aqueous NaCl-type fluid inclusion the final ice-melting temperature is −8.0 °C. Use S = 1.78θ − 0.0442θ² + 0.000557θ³, where θ is the freezing-point depression in °C (θ = 8.0 here) and S is the salinity in wt% NaCl equivalent. The salinity is ____ wt% NaCl equivalent (give the answer to two decimal places).
Numerical answer — type the value.
Show answer
Answer: 11.70
With θ = 8.0: 1.78 × 8.0 = 14.240; 0.0442 × 64 = 2.8288; 0.000557 × 512 = 0.2852. So S = 14.240 − 2.8288 + 0.2852 = 11.6964, which is 11.70 wt% NaCl equivalent. Taking θ = −8.0 without using its magnitude gives a negative nonsense value, and dropping the cubic term gives 11.41.A coal sample analysed on the as-received basis has moisture 7%, volatile matter 30% and ash 15%. The fixed carbon is the remainder after these three, and the fuel ratio is fixed carbon ÷ volatile matter. The fuel ratio is ____ (give the answer to one decimal place).
Numerical answer — type the value.
Show answer
Answer: 1.6
Fixed carbon = 100 − (7 + 30 + 15) = 48%. The fuel ratio is 48 / 30 = 1.6. Using 100 − (30 + 15) = 55 as fixed carbon, which leaves moisture in, gives 1.8, the usual slip.