Puzzles: Schedules, Floors, Boxes, Comparison and Tabulation
Floors and Stacked Boxes
In a floor puzzle the stem says which floor is numbered 1, almost always the lowest. In a stack of boxes, give position 1 to the bottom box and read "above" as a larger number. The counting formulas are the same as for a row. With n floors or n boxes, the k-th from the top is (n − k + 1)-th from the bottom, and the number of floors or boxes between the places a and b is |a − b| − 1, never |a − b|.
Worked example. Seven boxes are stacked. Box X is 3rd from the top and box Y is 2nd from the bottom. X is 7 − 3 + 1 = 5th from the bottom, so between positions 5 and 2 there are 5 − 2 − 1 = 2 boxes. Worked puzzle. Five boxes S, T, U, V, W are stacked. S is at the bottom, W is at the top, T is immediately above S, and V is above U. Then T is 2nd, W is 5th, and U and V fill positions 3 and 4 with V above U, so the stack from the bottom is S, T, U, V, W and exactly one box lies between T and V.
Days, Months and Dates
Day puzzles are arithmetic on a cycle of seven. Number the days Monday = 1 up to Sunday = 7 (Sunday as 0 also works) and move by a number of days modulo 7: after 100 days from Wednesday you move 100 mod 7 = 2 days and reach Friday. "The day after tomorrow" is two days ahead and "three days ago" is three days back. For schedules, the same idea gives a line of seven slots: Monday to Saturday are six slots, and "immediately after" means the next slot.
| Month group | Days | Odd days (days mod 7) |
|---|---|---|
| January, March, May, July, August, October, December | 31 | 3 |
| April, June, September, November | 30 | 2 |
| February | 28 (29 in a leap year) | 0 (1 in a leap year) |
Same date, later month. The weekday of the same date moves forward by the odd days of the months passed. Worked example: 10 January is a Friday in a non-leap year. January (3) and February (0) give 3 odd days, so 10 March is Friday + 3 = Monday. In a leap year February adds 1, giving 4 odd days and Tuesday. Counting weekdays: a 30-day month is 4 weeks plus 2 extra days, and a 31-day month is 4 weeks plus 3 extra days. A 31-day month beginning on a Saturday therefore has five Saturdays, five Sundays and five Mondays, because the extra days are the first ones.
Three-Variable Conditional Puzzles
A conditional puzzle gives a pool of candidates and rules, and asks who can or must be chosen. Translate every rule into one of four shapes. Together rule: "P and Q are never chosen together" means P and Q are not both in. If-then: "if R then S" forbids R without S, and its contrapositive "no S means no R" is the form that is often needed. Only if: "T only if P" means T cannot be in without P, so it behaves exactly like "if T then P". Exactly k: the team has exactly k members, so choose by elimination.
Worked example. Choose three of five officers P, Q, R, S, T so that (i) P and Q are not chosen together, (ii) if R is chosen then S is chosen, (iii) T is chosen only if P is chosen. T needs P, and P forbids Q, so a team with T is P, T and one of R or S; R would need S, which is a fourth member, so the team is P, S, T. Without T, the team is three of P, Q, R, S with rule (i): P, R, S or Q, R, S (P, Q, R and the other pairs fail a rule). The valid teams are therefore PRS, PST and QRS, and exactly one of P and Q is present in each.
Greater-Than Comparison Puzzles
A comparison puzzle gives pairs such as "A is taller than B" and asks who is tallest, who is second, or whether a relation is certain. Build a chain: draw an arrow from the taller to the shorter, join the pieces through shared names, and read the order off the longest path. Two facts are easy to lose. A relation is certain only when a path of arrows joins the two persons; two persons on different branches have no certain order. And in a group of n with distinct heights, a person's rank from the top plus rank from the bottom is n + 1.
Worked example. Seven persons have distinct heights and exactly two are taller than Rita. Rita is 3rd from the tallest, so she is 7 − 3 + 1 = 5th from the shortest. Worked puzzle. Five persons A to E: exactly two are shorter than A; B is taller than A; D is taller than C and C is taller than E; B is taller than D. A has exactly two below, so A is 3rd from the top. The persons above A are B and one more, and the chain D, C, E allows only D to be that one (if C or E were above A, D would be too, making three above A). B is taller than D, so the order is B, D, A, C, E and the second tallest is D.
Tabulation Puzzles and the Traps
A tabulation puzzle gives each item several attributes, say a person, a floor and a counter, and the grid has more than one block. Fix the attribute that carries order (days, floors) first, because order clues place items by counting. Then tie the other attributes to those slots one clue at a time. Worked example. Asha, Bimal and Charu sit on floors 1 to 3 and handle Cash, Loans and Deposits. Asha does not handle Cash; the Loans clerk is on a higher floor than the Cash clerk; Bimal is on floor 2 and does not handle Loans; Charu is not on floor 1. Charu is on floor 3 and Asha on floor 1. Asha is not Cash and cannot be Loans (nobody is below her), so Asha has Deposits. Bimal is not Loans, so Bimal has Cash and Charu has Loans.
| Floor | Person | Counter |
|---|---|---|
| 3 | Charu | Loans |
| 2 | Bimal | Cash |
| 1 | Asha | Deposits |
- Order first: place the ordered attribute before the unordered ones.
- Linked clues wait: do not guess an end of a link; write the pair and revisit it.
- Two-case clues: if a clue leaves two cases, both stay until a later clue kills one; a question then asks only what both share.
- Check at the end: re-read each clue against the finished table; a single violated clue invalidates every answer.
Key takeaways
- Use an elimination grid: tick and cross a fixed cell, cross an excluded one, write a link as a pair, and let single blanks force cells; read the quantity word (exactly, at least, at most) first.
- In a stack or on floors, k-th from the top is (n − k + 1)-th from the bottom and the number between two places is |a − b| − 1; convert every "gap" to gap + 1 places.
- Days run on a cycle of seven: move by the days mod 7; months of 31 days shift the weekday by 3 and those of 30 days by 2; a 31-day month has three days that occur five times.
- Translate each conditional rule to a shape (together, if-then, only if, exactly k), list every valid team once, and take the intersection for who must be in and the union for who can be in.
- In comparison puzzles, a relation is certain only along a path of arrows; rank from the top plus rank from the bottom is n + 1; two persons on different branches have no certain order.
- In tabulation, fix the ordered attribute first, attach the others one clue at a time, keep two-case clues alive, and re-check every clue against the finished table.
Practice questions (16)
Attempt each one before opening the answer. Every explanation names the tempting wrong option as well as the right one, because that is where marks are lost.
If the day after tomorrow is Friday, what day was it three days ago?
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Answer: C — Sunday
The day after tomorrow is Friday, so today is Wednesday. Three days before Wednesday is Sunday. Monday comes from counting only two days back, and Tuesday is yesterday.A month of 30 days begins on a Thursday. How many Fridays does it have?
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Answer: A — 5
30 days is 4 full weeks plus 2 extra days, and the extra days are the first two, Thursday and Friday. So Thursday and Friday occur five times each (Fridays on the 2nd, 9th, 16th, 23rd and 30th). Four counts only the full weeks.Nine boxes are stacked one above the other. Box P is 3rd from the top and box Q is 2nd from the bottom. How many boxes are between P and Q?
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Answer: B — 4
P is 9 − 3 + 1 = 7th from the bottom and Q is 2nd, so 7 − 2 − 1 = 4 boxes lie between them. Five is the position difference without removing P, and 3 and 6 result from mixing top and bottom counts.Seven persons have different heights, and exactly two of them are taller than Rita. What is Rita's position when counted from the shortest?
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Answer: D — 5th
Two taller means Rita is 3rd from the tallest, so from the shortest she is 7 − 3 + 1 = 5th. The 3rd is her position from the tallest, and the 4th assumes that three persons are taller.In a certain year, 15 August falls on a Monday. On which day of the week does 15 October of the same year fall?
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Answer: B — Saturday
From 15 August to 15 October is 31 days (August) plus 30 days (September), which is 61 days. 61 mod 7 = 5, so Monday + 5 is Saturday. Friday results from 60 days, which forgets that August has 31 days.Exactly two of three officers P, Q and R are selected for a panel. P and Q are never selected together. Which of the following is certain?
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Answer: A — R is selected
The possible pairs are PQ, PR and QR; PQ is forbidden, leaving PR and QR, and R is in both. P or Q alone is not certain, since either may be left out. Neither P nor Q would leave one person, which breaks the rule of exactly two.Five officers K, L, M, N and O work on five floors of a building, numbered 1 (lowest) to 5 (top), one per floor, in five different departments: Loans, Cash, Deposits, Accounts and Care. M works on the top floor and N on the lowest. L works immediately above N. K works on a higher floor than O. K is in Deposits. The Care officer works above the Deposits officer. The Loans officer works immediately below the Accounts officer. N is not in Loans. Who works immediately above the Accounts officer?
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Answer: D — K
M is on floor 5, N on 1 and L on 2; K is above O, so O is on 3 and K on 4. K has Deposits, Care is above it (M), and Loans sits just below Accounts. N is not Loans, so Cash is N and Loans-Accounts are L (floor 2) and O (floor 3). The Accounts officer is O, and K is immediately above. L is the Loans officer, the swap that arises from reversing the Loans-Accounts pair.Six boxes A, B, C, D, E and F are stacked one above the other. D is at the bottom. Exactly two boxes are kept between D and F, and F is above D. B is the fifth box from the bottom. F is kept immediately above A. C is kept somewhere between D and E, with D below C. How many boxes are kept between C and E?
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Answer: C — 3
D is position 1 and F is position 4, so A is 3 and B is 5. C and E are left for positions 2 and 6, and C is between D and E, so C is 2 and E is 6. The boxes between C and E are A, F and B, which is 3. Two counts only A and F.Six auditors P, Q, R, S, T and U each inspect a branch on a different day from Monday to Saturday of one week. T inspects on the day immediately after R, and P on the day immediately after T. U inspects on Thursday. S does not inspect on the day immediately before or immediately after U. Who inspects on the day immediately after U?
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Answer: A — Q
R, T, P run on three consecutive days, and Thursday is U's, so they must be Monday to Wednesday. Q and S take Friday and Saturday; S cannot be next to U on Friday, so S is Saturday and Q is Friday. S is the tempting answer for the last day of the week.Five camps A, B, C, D and E were held in five different months of one year, namely January, March, May, August and October, one camp per month. D was held three months after E. B was held later than D. A was held earlier than E but later than C. Which camp was held exactly two months before camp E?
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Answer: D — A
Only May and August are three months apart, so E is May and D is August. B is later than D, so October. A and C take January and March with C before A, so C is January and A is March, exactly two months before May. C is January, four months before E.Five officers P, Q, R, S and T attend interviews on five different dates of a month, namely the 3rd, 8th, 11th, 17th and 24th, one on each date. S was interviewed exactly 7 days after R. Q was interviewed on an even date. T was interviewed earlier than P. How many days after P's interview was R's interview held?
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Answer: B — 6
The only pair 7 days apart is 17 and 24, so R is 17 and S is 24. The only even date is 8, so Q is 8. T and P take 3 and 11 with T earlier, so P is 11 and R's date is 17 − 11 = 6 days later. Nine would measure from Q.A team of three is chosen from six officers A, B, C, D, E and F under these rules. If A is chosen, B must be chosen. C and D are never chosen together. E can be chosen only if A is chosen. F can be chosen only if D is chosen. If C is in the team, which two others are definitely in it?
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Answer: C — A and B
With C in, D is out, so F is out (F needs D). That leaves A, B, E for the other two places. E needs A, and A needs B, so the pair is A and B, giving ABC. B and D fails as D cannot sit with C, and A and E fails as A needs B.Five persons A, B, C, D and E have different heights. Exactly two persons are shorter than A. B is taller than A. D is taller than C, and C is taller than E. B is taller than D. Who is the second tallest of the five?
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Answer: A — D
A has exactly two below, so A is 3rd from the top. The chain D, C, E puts C and E below A, and B is above A, so the top three are B, D, A. B is the tallest because B is taller than D, so D is second. A is only third.Four officers W, X, Y and Z work in four different departments, namely Cash, Loans, Deposits and Enquiry, and each took leave on a different day from Monday to Thursday. The Loans officer took leave on the day immediately before Z. X took leave earlier in the week than Z. The Deposits officer took leave on the day immediately before X. Exactly one day lies between the leave days of the Loans officer and the Cash officer. Y did not take leave on Monday or Thursday. In which department does W work?
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Answer: B — Cash
X is earlier than Z, the Loans officer is the day before Z and the Deposits officer the day before X. This makes X the Loans officer; the only other case, X on Tuesday and Z on Thursday, leaves Cash no free day two days from Loans. So Deposits, X (Loans) and Z fall on consecutive days, and Cash is two days from X. The only fit is Deposits Tuesday, X Wednesday, Z Thursday, Cash Monday. Y cannot take Monday, so Y is Tuesday (Deposits) and W is Monday, in Cash. Loans is X, not W.Five persons K, L, M, N and O live on five different floors of a building, numbered 1 (lowest) to 5 (top), one per floor. O lives on the third floor. K lives on a higher floor than O. O lives immediately above L. M lives on a higher floor than N. Which of the following is definitely true?
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Answer: D — N lives on the lowest floor
L is on floor 2 and O on 3, leaving floors 1, 4 and 5 for K, M and N. K is above O, so K is on 4 or 5 and M is above N, so N is on floor 1; M and K share 4 and 5 in either order. N on floor 1 is the only fact common to both cases. K on top and M above K each hold in one case only.A is taller than B. C is taller than B. B is taller than D. E is taller than C. D is taller than F. Statements. P: E is taller than F. Q: A is taller than D. R: A is taller than C. S: C is taller than F. Which of the statements are definitely true?
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Answer: C — Only P, Q and S
The paths are E > C > B > D > F and A > B. P, Q and S follow along these paths: E to F, A to D through B, and C to F. R has no path between A and C, since both are only above B, so it is not certain. Only P and Q wrongly drops the path C > B > D > F.