Surface Chemistry — Adsorption, Catalysis and Colloids
Catalysis and Its Vocabulary
A catalyst provides an alternative reaction path of lower activation energy, unchanged in amount at the end. Homogeneous catalysis has catalyst and reactants in the same phase, as in the lead-chamber process where NO(g) catalyses SO₂(g) oxidation. Heterogeneous catalysis has them in different phases, as in Haber's iron catalysing gases — and this is where surface chemistry matters, because the reaction happens on the surface and so finely divided or porous catalysts work best.
| Term | Meaning | Example |
|---|---|---|
| Promoter | Increases the activity of a catalyst | Mo with Fe in the Haber process |
| Poison | Destroys activity, often by chemisorbing irreversibly | CO on the Fe catalyst; S on Pt |
| Autocatalysis | A product catalyses the reaction, so the rate rises with time | Mn²⁺ in KMnO₄ titrations |
| Shape-selective catalysis | Pore size decides which molecules can react | ZSM-5 zeolite converting alcohols to petrol |
| Enzyme catalysis | Highly specific, works near 298–310 K and a narrow pH | Maltase converting maltose to glucose |
Colloids — Classification and Behaviour
A colloid has dispersed particles between 1 and 1000 nm — larger than a true solution, smaller than a suspension. That size range is the whole reason for its behaviour: the particles are big enough to scatter light but small enough that Brownian motion keeps them from settling. Lyophilic colloids such as starch or gelatin are reversible and stabilised by strong solvent interaction; lyophobic colloids such as metal sols are irreversible and stabilised only by charge, which is why they are easily coagulated.
| Property | What is observed | Cause |
|---|---|---|
| Tyndall effect | A visible beam through the sol | Scattering by particles comparable to λ of light |
| Brownian motion | Ceaseless zig-zag movement | Uneven bombardment by solvent molecules |
| Electrophoresis | Particles migrate in an electric field | Every colloidal particle carries a charge |
| Coagulation | The sol settles out as a precipitate | Added electrolyte neutralises the charge |
| Dialysis | Electrolyte removed through a membrane | Ions pass, colloidal particles cannot |
An emulsion is a colloid of one liquid in another, needing an emulsifier to persist: soap stabilises oil-in-water, which is how washing works, while milk is fat-in-water stabilised by casein and butter is the reverse, water-in-oil. A micelle forms above a critical concentration and temperature when soap molecules aggregate with hydrocarbon tails inward and ionic heads outward, trapping grease in the core — the reason soap cleans at all, and the reason it fails in hard water, where Ca²⁺ and Mg²⁺ precipitate the soap as an insoluble scum before micelles can form.
Key takeaways
- Adsorption is a surface phenomenon, absorption is bulk, sorption is both happening at once.
- Adsorption is always exothermic, because the adsorbate loses freedom so ΔS is negative.
- Physisorption is weak, reversible, non-specific and multilayer; chemisorption is strong, specific and monolayer.
- Chemisorption first rises then falls with temperature, because it needs activation energy; physisorption only falls.
- Freundlich: x/m = kp^(1/n), so log(x/m) against log p is linear with slope 1/n.
- A promoter boosts a catalyst, a poison destroys it, and in autocatalysis a product is the catalyst.
- Colloidal particles are 1–1000 nm: big enough to scatter light, small enough to resist settling.
- Hardy–Schulze: the higher the charge on the coagulating ion, the more effective — Al³⁺ > Ba²⁺ > Na⁺.
Practice questions (8)
Attempt each one before opening the answer. Every explanation names the tempting wrong option as well as the right one, because that is where marks are lost.
Adsorption of a gas on a solid is always accompanied by:
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Answer: B — A decrease in enthalpy
A gas molecule landing on a surface loses translational freedom, so ΔS is negative; for the process to be spontaneous with ΔG negative, ΔH must be negative — adsorption is always exothermic. This is also why heating reduces the extent of physisorption, and why adsorbed gases can be driven off by warming the adsorbent.The extent of a certain adsorption first increases and then decreases with rising temperature. The process is:
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Answer: B — Chemisorption
Chemisorption forms a real chemical bond and therefore requires activation energy, so at low temperature warming supplies the energy needed and adsorption increases; once the barrier is cleared, the exothermic equilibrium takes over and further heating desorbs the gas. Physisorption needs no activation energy and so falls monotonically from the start, which is exactly the contrast the graph is testing.In the Freundlich isotherm x/m = kp^(1/n), the plot of log(x/m) against log p gives a straight line of slope:
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Answer: C — 1/n
Taking logarithms gives log(x/m) = log k + (1/n) log p, so the slope is 1/n and the intercept log k. Since 1/n lies between 0 and 1, the line is always less steep than 45°; the limiting cases 1/n = 1 and 1/n = 0 correspond to the low-pressure proportional region and the high-pressure saturated plateau respectively.The slow start followed by rapid completion in the titration of oxalic acid with KMnO₄ is due to:
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Answer: B — Autocatalysis by the Mn²⁺ produced
Mn²⁺ is a product of the reduction of MnO₄⁻ and it catalyses the very reaction that makes it, so at the outset there is no catalyst and the reaction crawls, then accelerates as product accumulates. A promoter would have to be added deliberately alongside a catalyst, and poisoning would slow the reaction rather than speed it up — both point the wrong way for the observation described.Which ion would be most effective in coagulating a negatively charged As₂S₃ sol?
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Answer: C — Al³⁺
By the Hardy–Schulze rule the coagulating power of an ion rises steeply with its charge, so for a negative sol the trivalent Al³⁺ is far more effective than Ba²⁺ or Na⁺. Cl⁻ is negative like the sol itself and would simply be repelled, so it cannot coagulate it at all — the sign of the ion must be opposite to that of the particles.The Tyndall effect is observed in a colloid because the particles:
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Answer: B — Are comparable in size to the wavelength of light and scatter it
Scattering requires particles of a size comparable to the wavelength of visible light, which is precisely the 1–1000 nm colloidal range — a true solution has particles far too small to scatter, so no beam is visible. Charge explains electrophoresis and coagulation, and Brownian motion explains why the sol does not settle, but neither produces the visible beam.Delta formation where a river meets the sea is an example of:
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Answer: B — Coagulation of a colloid by electrolytes
River water carries a clay sol whose like-charged particles repel and stay suspended; the concentrated electrolytes in sea water neutralise that charge, so the particles clump and settle out as a delta. Dialysis is the opposite process of removing electrolyte to preserve a sol, and peptisation is the conversion of a precipitate back into a colloid — both move in the wrong direction here.Molybdenum added to the iron catalyst in the Haber process acts as a:
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Answer: B — Promoter
A promoter is a substance with no catalytic activity of its own that increases the activity of the actual catalyst, which is exactly molybdenum's role alongside iron. A poison would destroy activity — CO does that to this very catalyst — and molybdenum does not substitute for iron, since removing the iron would stop the reaction regardless of how much Mo were present.