Mammalian Cell Biology, Human Anatomy and Physiology: The Cell, Tissues, Homeostasis and the Organ Systems

Section 7 of the GATE Biomedical Engineering (BM) paper is short in the syllabus and wide in scope: the basics of the cell, the types of tissue and the organ systems; homeostasis; and the basics and physiological aspects of seven named systems — musculoskeletal, respiratory, circulatory, excretory, endocrine, nervous and gastro-intestinal. This chapter keeps to that wording and to the depth an engineer needs, which is the physiology that instruments measure: the membrane potential that every biopotential starts from, the pressures, flows and volumes of the heart and lungs, the filtration rate of the kidney, and the feedback loops that hold the internal environment steady. It runs from the cell outwards, taking the organ systems in pairs where their physiology is linked.

1. The cell, the membrane and the membrane potential

Organelles and what they do
StructureFunction
Plasma membrane — phospholipid bilayer with proteins (fluid mosaic)selective barrier; carries channels, pumps, carriers and receptors
Nucleusholds the DNA; transcription of genes into RNA
Ribosomes and rough endoplasmic reticulumprotein synthesis; proteins for export are made on the rough ER
Smooth endoplasmic reticulumlipid synthesis, detoxification; stores Ca²⁺ in muscle (sarcoplasmic reticulum)
Golgi apparatusmodifies, sorts and packages proteins into vesicles
Mitochondriaaerobic respiration; most of the cell’s ATP
Lysosomesenzymatic digestion of worn-out components and ingested material
Cytoskeletonshape, movement and transport inside the cell

Substances cross the membrane by simple diffusion (O₂, CO₂, lipid-soluble molecules), facilitated diffusion through channels and carriers (glucose, ions), both down a gradient and without energy, and by active transport against a gradient using ATP. The Na⁺/K⁺-ATPase moves 3 Na⁺ out and 2 K⁺ in per ATP, which keeps K⁺ high inside and Na⁺ high outside. Osmosis moves water towards the side of higher solute concentration.

An ion that can cross the membrane settles at the potential where its electrical and diffusional drives balance, the Nernst potential E = (RT/zF) ln(C_out/C_in); at 37 °C, RT/F ≈ 26.7 mV, so for a monovalent ion E ≈ 61.5 log₁₀(C_out/C_in) mV. With several permeant ions the resting potential follows the Goldman–Hodgkin–Katz equation, V_m = (RT/F) ln[(P_K K_o + P_Na Na_o + P_Cl Cl_i)/(P_K K_i + P_Na Na_i + P_Cl Cl_o)] — chloride enters with inside and outside swapped because its charge is negative. At rest the membrane is far more permeable to K⁺ than to Na⁺, so V_m sits near E_K, typically −70 mV in neurons and about −90 mV in ventricular muscle.

An action potential starts when a stimulus depolarises the membrane to threshold: voltage-gated Na⁺ channels open and Na⁺ influx drives the potential positive; Na⁺ channels then inactivate and delayed K⁺ channels open, and K⁺ efflux repolarises it, with a brief after-hyperpolarisation. It is all-or-none — a stronger stimulus raises the firing rate, not the amplitude. During the absolute refractory period no second spike can be fired; during the relative one only a stronger stimulus succeeds. Myelin confines excitation to the nodes of Ranvier, so conduction is saltatory and much faster than in unmyelinated fibres of the same diameter.

2. Tissues, organ systems and homeostasis

The four primary tissues
TissueFeaturesExamples
Epithelialclosely packed cells on a basement membrane; covers, lines, secretes, absorbs; avascularskin epidermis, gut lining, alveolar wall, glands
Connectivecells scattered in an extracellular matrix of fibres (collagen, elastin) and ground substancebone, cartilage, tendon, ligament, adipose tissue, blood
Musclecontractile cells: skeletal (striated, voluntary), cardiac (striated, involuntary, intercalated discs), smooth (non-striated, involuntary)biceps, myocardium, walls of vessels and gut
Nervousneurons that conduct impulses and glial cells that support thembrain, spinal cord, nerves

Cells form tissues, tissues form organs, and organs working together form organ systems. Homeostasis is the maintenance of a steady internal environment — temperature, blood glucose, pH, osmolality, blood pressure — against disturbance. A homeostatic loop has a receptor (sensor), a control centre that compares the input with a set point, and an effector that acts, exactly the structure of a feedback control system.

  • Negative feedback opposes the change and is the rule: a rise in body temperature, sensed by the hypothalamus, triggers sweating and skin vasodilation; a rise in blood glucose triggers insulin release.
  • Positive feedback amplifies the change until an event ends it: oxytocin during labour (contractions stretch the cervix, which releases more oxytocin), the clotting cascade, and the Na⁺ influx of the rising action potential.

3. The musculoskeletal and nervous systems

The adult skeleton has 206 bones, divided into the axial skeleton (skull, vertebral column, ribs, sternum) and the appendicular skeleton (limbs and their girdles). It supports, protects, provides levers for movement, stores calcium and phosphate, and houses the red marrow that makes blood cells. Joints are fibrous (immovable), cartilaginous (slightly movable) or synovial (freely movable, with a capsule, synovial fluid and articular cartilage) — hinge (elbow, knee), ball-and-socket (hip, shoulder), pivot, saddle, condyloid and gliding types.

A skeletal muscle fibre contains myofibrils built from sarcomeres between Z lines: thick myosin filaments form the A band, thin actin filaments reach in from each Z line, and the I band and H zone are where they do not overlap. In excitation–contraction coupling the motor neuron releases acetylcholine at the neuromuscular junction, the muscle action potential travels down the T-tubules, the sarcoplasmic reticulum releases Ca²⁺, Ca²⁺ binds troponin and moves tropomyosin off actin’s binding sites, and myosin heads cycle using ATP. By the sliding-filament mechanism the filaments slide past each other: the I band and H zone shorten while the A band keeps its length. One motor neuron and the fibres it supplies form a motor unit; force is graded by recruiting more units and by raising the firing rate until twitches fuse into tetanus.

The central nervous system is the brain and spinal cord; the peripheral nervous system is the cranial and spinal nerves, divided into the somatic system (voluntary, to skeletal muscle) and the autonomic system. The autonomic system has a sympathetic division (“fight or flight”: raises heart rate and blood pressure, dilates pupils and airways; its postganglionic transmitter is mostly noradrenaline) and a parasympathetic division (“rest and digest”: slows the heart, promotes digestion; transmitter acetylcholine, carried largely by the vagus nerve). A neuron passes its signal to the next across a synapse, where a neurotransmitter released from vesicles binds receptors on the postsynaptic membrane. A reflex arc — receptor, afferent neuron, integrating centre, efferent neuron, effector — produces a rapid automatic response such as the knee jerk.

4. The circulatory and respiratory systems

The heart is two pumps in series. The right side receives deoxygenated blood from the venae cavae into the right atrium and sends it through the tricuspid valve and right ventricle to the lungs via the pulmonary artery; the left side receives oxygenated blood from the pulmonary veins and pumps it through the mitral valve, left ventricle and aortic valve to the body. Excitation starts at the sinoatrial (SA) node, the normal pacemaker, spreads over the atria, is delayed at the atrioventricular (AV) node so the atria finish filling the ventricles, and runs down the bundle of His and the Purkinje fibres. In the ECG the P wave is atrial depolarisation, the QRS complex ventricular depolarisation and the T wave ventricular repolarisation.

  • Cardiac output CO = heart rate × stroke volume, about 5 L/min at rest; stroke volume = end-diastolic − end-systolic volume, and ejection fraction = SV/EDV, normally above about 55%.
  • Mean arterial pressure ≈ diastolic + (systolic − diastolic)/3, because the heart spends longer in diastole; MAP = CO × total peripheral resistance.
  • Poiseuille’s law for steady laminar flow of a Newtonian fluid in a rigid tube: Q = πr⁴ΔP/(8μL), so the resistance is 8μL/(πr⁴). Halving a vessel’s radius raises its resistance sixteen-fold — why arterioles, by small changes in diameter, control the distribution of flow. Blood is non-Newtonian and vessels are elastic, so this is an idealisation, but its r⁴ dependence governs the physiology.
  • Blood is plasma plus formed elements — red cells (O₂ transport by haemoglobin), white cells (defence) and platelets (clotting).

Air passes through the nose, pharynx, larynx, trachea, bronchi and bronchioles to about 300 million alveoli, where gas exchange occurs across a very thin membrane. Inspiration is active: the diaphragm and external intercostals enlarge the thorax, intrapleural pressure falls, and by Boyle’s law alveolar pressure drops below atmospheric so air flows in; quiet expiration is passive recoil. Oxygen and CO₂ move by diffusion down partial-pressure gradients (alveolar pO₂ about 100 mmHg against about 40 mmHg in mixed venous blood), and haemoglobin’s sigmoid dissociation curve lets blood load oxygen fully in the lungs and release it in the tissues.

Lung volumes and capacities
QuantityDefinitionMeasured by spirometry?
Tidal volume (TV)volume of a quiet breath, about 500 mLyes
Vital capacity (VC)IRV + TV + ERV — the largest breath out after the largest breath inyes
Residual volume (RV)air left after maximal expirationno — needs gas dilution or body plethysmography
Functional residual capacity (FRC)ERV + RV — the volume at the end of a quiet expirationno (contains RV)
Total lung capacity (TLC)VC + RVno (contains RV)

Minute ventilation is TV × breathing rate, but the first ~150 mL of each breath only fills the conducting airways (the anatomical dead space), so alveolar ventilation = (TV − V_D) × rate — about (500 − 150) × 12 = 4.2 L/min at rest.

5. The excretory, endocrine and gastro-intestinal systems

Each kidney has about a million nephrons. Blood is filtered in the glomerulus into Bowman’s capsule — the glomerular filtration rate (GFR) is about 125 mL/min — and the filtrate is modified along the proximal tubule (bulk reabsorption of glucose, amino acids, Na⁺ and water), the loop of Henle (builds the medullary concentration gradient), the distal tubule and the collecting duct (fine control by hormones). Renal clearance C = UV/P, urine concentration times urine flow over plasma concentration; for inulin, which is filtered and neither reabsorbed nor secreted, clearance equals GFR. ADH (vasopressin) makes the collecting duct permeable to water and concentrates the urine; aldosterone increases Na⁺ reabsorption and K⁺ secretion; the renin–angiotensin–aldosterone system restores blood pressure and volume.

Endocrine glands and their principal hormones
GlandHormoneMain action
Hypothalamus / posterior pituitaryADH, oxytocinwater retention; uterine contraction and milk ejection
Anterior pituitaryGH, TSH, ACTH, FSH, LH, prolactingrowth; control of the thyroid, adrenal cortex and gonads
ThyroidT₃, T₄; calcitoninmetabolic rate; lowers blood Ca²⁺
Parathyroidparathyroid hormoneraises blood Ca²⁺
Adrenal cortex / medullacortisol, aldosterone / adrenaline, noradrenalinestress response, Na⁺ balance / fight-or-flight
Pancreatic isletsinsulin (β cells), glucagon (α cells)lowers / raises blood glucose

The gastro-intestinal tract runs mouth, pharynx, oesophagus, stomach, small intestine (duodenum, jejunum, ileum) and large intestine, with the salivary glands, liver, gall bladder and pancreas as accessory organs. Digestion is mechanical and chemical: salivary amylase starts on starch; the stomach’s acid and pepsin begin protein digestion; pancreatic juice brings trypsin (proteins), amylase (carbohydrates) and lipase (fats), with bile from the liver emulsifying fats. Nearly all absorption happens in the small intestine, whose folds, villi and microvilli multiply its surface area; the large intestine absorbs water and electrolytes. Peristalsis — waves of smooth-muscle contraction under the enteric nervous system — moves the contents along.

ℹ️ Why an engineer needs these numbers
Every instrument in the paper is designed around them: an ECG front end around a 1 mV signal at the skin, a ventilator around a 500 mL tidal volume and the dead space, a dialyser around the clearance a kidney would provide, a flowmeter around the r⁴ law. Knowing the physiological value is how an implausible answer is caught.

Key takeaways

  • Nernst: E = 61.5 log₁₀(C_out/C_in) mV at 37 °C for a monovalent ion; Goldman weights each ion by its permeability, chloride with inside and outside swapped.
  • Na⁺/K⁺ pump: 3 Na⁺ out, 2 K⁺ in; the action potential is Na⁺ in, then K⁺ out, all-or-none, with refractory periods.
  • Homeostasis is negative feedback (receptor, control centre, effector); positive feedback appears in labour, clotting and the rising spike.
  • CO = HR × SV, MAP ≈ DBP + (SBP − DBP)/3, Poiseuille Q = πr⁴ΔP/(8μL); alveolar ventilation = (TV − dead space) × rate.
  • Clearance C = UV/P and inulin clearance = GFR ≈ 125 mL/min; RV, FRC and TLC cannot be measured by spirometry alone.

Practice questions (15)

Attempt each one before opening the answer. Every explanation names the tempting wrong option as well as the right one, because that is where marks are lost.

  1. Extracellular K⁺ is 4 mM and intracellular K⁺ is 140 mM. Using E = 61.5 log₁₀(C_out/C_in) mV at 37 °C, the K⁺ equilibrium potential (in mV), rounded to the nearest whole number, is ____.

    Numerical answer — type the value.

    Show answer

    Answer: -95

    E_K = 61.5 log₁₀(4/140) = 61.5 × (−1.544) = −94.96 mV ≈ −95 mV, inside negative because K⁺ tends to leak out. Inverting the ratio gives +95 mV; using log₁₀(140/4) with a positive sign is the same slip. Type the answer as -95.
  2. A cell at 37 °C has K⁺ 4 mM outside and 140 mM inside, Na⁺ 145 mM outside and 12 mM inside, Cl⁻ 110 mM outside and 10 mM inside, with relative permeabilities P_K : P_Na : P_Cl = 1 : 0.04 : 0.45. Using the Goldman equation with 61.5 log₁₀, the resting potential (in mV), to one decimal place, is ____.

    Numerical answer — type the value.

    Show answer

    Answer: -69.1

    Numerator P_K K_o + P_Na Na_o + P_Cl Cl_i = 4 + 5.8 + 4.5 = 14.3; denominator P_K K_i + P_Na Na_i + P_Cl Cl_o = 140 + 0.48 + 49.5 = 189.98. V_m = 61.5 log₁₀(14.3/189.98) = 61.5 × (−1.1234) = −69.1 mV. Treating chloride like a cation (Cl_o on top) gives about −24 mV, which is the usual mistake. Type the answer as -69.1.
  3. Per molecule of ATP hydrolysed, the Na⁺/K⁺-ATPase moves

    1. 3 Na⁺ out and 2 K⁺ in
    2. 2 Na⁺ out and 3 K⁺ in
    3. 3 Na⁺ in and 2 K⁺ out
    4. 1 Na⁺ out and 1 K⁺ in
    Show answer

    Answer: A — 3 Na⁺ out and 2 K⁺ in

    The pump exports three sodium ions and imports two potassium ions, which keeps Na⁺ high outside and K⁺ high inside and makes the pump itself slightly electrogenic (one net positive charge out per cycle). Reversing either the numbers or the directions describes a pump that would run down the very gradients it exists to build.
  4. Which is an example of positive feedback in human physiology?

    1. oxytocin release during labour
    2. sweating when body temperature rises
    3. insulin release when blood glucose rises
    4. the baroreceptor reflex slowing the heart when pressure rises
    Show answer

    Answer: A — oxytocin release during labour

    Uterine contractions stretch the cervix, which drives more oxytocin release and stronger contractions, a loop that amplifies until delivery ends it. Sweating, insulin release and the baroreflex each oppose the disturbance that triggered them, which is negative feedback.
  5. A heart beats at 72 per minute with an end-diastolic volume of 120 mL and an end-systolic volume of 50 mL. The cardiac output (in L/min), to two decimal places, is ____.

    Numerical answer — type the value.

    Show answer

    Answer: 5.04

    SV = EDV − ESV = 70 mL, so CO = 72 × 70 = 5040 mL/min = 5.04 L/min; the ejection fraction is 70/120 = 58%. Multiplying by the end-diastolic volume instead gives 8.64 L/min, which counts blood that never leaves the ventricle.
  6. A blood pressure of 120/80 mmHg corresponds to an estimated mean arterial pressure (in mmHg), to one decimal place, of ____.

    Numerical answer — type the value.

    Show answer

    Answer: 93.3

    MAP ≈ DBP + (SBP − DBP)/3 = 80 + 40/3 = 93.3 mmHg. The simple average, 100 mmHg, overweights systole — the heart spends about two-thirds of each cycle in diastole.
  7. Blood (viscosity 3.5 × 10⁻³ Pa·s, treated as Newtonian) flows steadily through a rigid tube of radius 2 mm and length 10 cm under a pressure difference of 100 Pa. By Poiseuille’s law the flow rate (in mL/s), to two decimal places, is ____.

    Numerical answer — type the value.

    Show answer

    Answer: 1.8

    Q = πr⁴ΔP/(8μL) = π × (2 × 10⁻³)⁴ × 100/(8 × 3.5 × 10⁻³ × 0.1) = 5.027 × 10⁻⁹/2.8 × 10⁻³ = 1.795 × 10⁻⁶ m³/s = 1.80 mL/s. Using the diameter in place of the radius multiplies the answer by 16, the r⁴ law at work.
  8. A person breathes 12 times a minute with a tidal volume of 500 mL and an anatomical dead space of 150 mL. The alveolar ventilation (in L/min), to one decimal place, is ____.

    Numerical answer — type the value.

    Show answer

    Answer: 4.2

    V̇_A = (TV − V_D) × rate = (500 − 150) × 12 = 4200 mL/min = 4.2 L/min. 6.0 L/min is the minute ventilation, which counts the air that only reaches the conducting airways and never takes part in gas exchange.
  9. Urine inulin is 25 mg/mL, urine flow is 1 mL/min and plasma inulin is 0.2 mg/mL. The glomerular filtration rate (in mL/min) is ____.

    Numerical answer — type the value.

    Show answer

    Answer: 125

    Inulin is freely filtered and neither reabsorbed nor secreted, so GFR = UV/P = 25 × 1/0.2 = 125 mL/min. Inverting the ratio gives 0.008, and forgetting the urine flow happens to give the same number here only because V = 1 mL/min.
  10. Which statements about organ-system physiology are correct?

    1. insulin lowers blood glucose
    2. ADH increases water reabsorption in the collecting ducts
    3. pepsin is the main fat-digesting enzyme of the stomach
    4. the SA node is the normal pacemaker of the heart
    Show answer

    Answer: A — insulin lowers blood glucose; B — ADH increases water reabsorption in the collecting ducts; D — the SA node is the normal pacemaker of the heart

    Insulin promotes glucose uptake and storage, ADH inserts water channels in the collecting duct, and the SA node has the fastest intrinsic rate and so sets the heartbeat. Pepsin digests proteins; fats are digested mainly by pancreatic lipase after emulsification by bile.
  11. Which of these cannot be measured with a simple spirometer?

    1. residual volume
    2. tidal volume
    3. vital capacity
    4. expiratory reserve volume
    Show answer

    Answer: A — residual volume

    A spirometer records only air that moves in and out of the mouth. The residual volume stays in the lungs even after maximal expiration, so it — and every capacity containing it (FRC, TLC) — needs gas dilution or body plethysmography.
  12. Which statements about the nerve action potential are correct?

    1. its rising (depolarising) phase is due to Na⁺ influx
    2. during the absolute refractory period no second action potential can be fired, however strong the stimulus
    3. myelination increases conduction velocity through saltatory conduction
    4. above threshold, its amplitude increases with stimulus strength
    Show answer

    Answer: A — its rising (depolarising) phase is due to Na⁺ influx; B — during the absolute refractory period no second action potential can be fired, however strong the stimulus; C — myelination increases conduction velocity through saltatory conduction

    Voltage-gated Na⁺ channels drive the upstroke, their inactivation creates the absolute refractory period, and myelin forces excitation to jump between nodes of Ranvier. The spike is all-or-none: stimulus strength is coded in firing frequency, not in amplitude.
  13. Blood is classified as which primary tissue type?

    1. connective tissue
    2. epithelial tissue
    3. muscle tissue
    4. nervous tissue
    Show answer

    Answer: A — connective tissue

    Blood is a connective tissue: its cells are dispersed in an extracellular matrix, the plasma, as in bone and cartilage where the matrix is solid. It lines nothing and is not contractile or excitable, which rules out the other three.
  14. During contraction of a skeletal muscle sarcomere, which band keeps its length?

    1. the A band
    2. the I band
    3. the H zone
    4. the whole sarcomere between Z lines
    Show answer

    Answer: A — the A band

    The A band is the length of the myosin filaments, and filaments do not shorten — they slide. As overlap increases the I band (actin only) and H zone (myosin only) narrow and the Z lines move closer, so the sarcomere shortens while the A band stays constant.
  15. A subject has total lung capacity 6000 mL, vital capacity 4800 mL and expiratory reserve volume 1200 mL. The functional residual capacity (in mL) is ____.

    Numerical answer — type the value.

    Show answer

    Answer: 2400

    RV = TLC − VC = 6000 − 4800 = 1200 mL, and FRC = ERV + RV = 1200 + 1200 = 2400 mL. Quoting 1200 mL gives the residual volume alone; TLC − ERV = 4800 mL is the inspiratory capacity plus RV, not FRC.